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Salsk061 [2.6K]
3 years ago
9

Protons and neutrons are found in the nucleus. these two types of charges are referred to collectively as _____

Chemistry
1 answer:
solmaris [256]3 years ago
4 0

Answer:

Nucleon

Explanation:

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How many valence electrons are in N2O? SeCl2? PBr3?
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Here is the answer for the three of them
<span>N20 = 16 e-
</span><span>SeCl2 =20
</span><span>PBr3 = 26 
Remember that t</span><span>o find the valence electrons in an atom you need to identify what group the element is in. An element in group 1A has 1 valence electron. If the element is in group 2A, then it has two valence electrons.</span>
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Radio stations identify themselves by their position on the radio dial such as 90.1 and 93.3. This number is based on the number
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<span>D. frequency is the answer</span>
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L and D forms of a molecule are what kind of isomers?
kotegsom [21]

Answer:

enantiomers

Explanation:

L and D stand for levorotatory and dextrorotatory respectively. A levorotatory molecule will rotate the plane of plane polarised light left and a dextrorotatory molecule will rotate the plane of plane polarised light right.  L and D molecules are non superimposable mirror image of each other. Therefore they are also known as enantiomers.

6 0
3 years ago
Read 2 more answers
In a chemical reaction,_______________are the substances present after the reaction.
dsp73

Answer:

In a chemical reaction, <u>products</u> are the substances present after the reaction

8 0
3 years ago
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The data below shows the change in concentration of dinitrogen pentoxide over time, at 330 K, according to the following process
tensa zangetsu [6.8K]

Answer: a) 1.7\times 10^{-4}

b) 3.4\times 10^{-4}

Explanation:

The reaction is :

2N_2O_5(g)\rightarrow 4NO_2(g)+O_2(g)

Rate = Rate of disappearance of N_2O_5 = Rate of appearance of NO_2

Rate =  -\frac{d[N_2O_5]}{2dt} = \frac{d[NO_2]}{4dt}

Rate of disappearance of N_2O_5 = \frac{\text {change in concentration}}{time} = \frac{0.100-0.066}{200-0}=1.7\times 10^{-4}

a) Rate of disappearance of N_2O_5 = -\frac{d[N_2O_5]}{2dt}

Rate of appearance of NO_2 = \frac{d[NO_2]}{4dt}

b) Rate of appearance of NO_2 =  \frac{d[NO_2]}{dt}=2\times 1.7\times 10^{-4}}=3.4\times 10^{-4}

8 0
3 years ago
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