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3 years ago

When a company in the United States employs people in India to answer their customer service calls this is an example of

Engineering

1 answer:

fgiga [73]3 years ago

3 0

Answer is : B Outsourcing.

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Calculate the wire pressure for a round copper bar with an original cross-sectional area of 12.56 mm2 to a 30% reduction of area

dybincka [34]

Answer:153.76 MPa

Explanation:

$Initial Area\left ( A_0\right )=12.56 mm^2$

$Final Area\left ( A_f\right )=0.7\times 12.56 mm^2=8.792 mm^2$

$Die angle=30^{\circ}$

$\alpha =\frac{30}{2}=15^{\circ}$

$\mu =0.08$

$Yield stress\left ( \sigma _y \right )=350 MPa$

$B=\mu cot\left ( \aplha\right )=0.2985$

$\sigma _{pressure}=\sigma _y\left [\frac{1+B}{B}\right ]\left [ 1-\frac{A_f}{A_0}\right ]^B$

$\sigma _{pressure}=350\left [\frac{1+0.2985}{0.2985}\right ]\left [ 1-\frac{8.792}{12.56}\right ]^{0.2985}$

$\sigma _{pressure}=153.76 MPa$

8 0

3 years ago

What is electrical energy used for?

FromTheMoon [43]

Answer:

to power devices appliances and some methods of transportation

Explanation:

6 0

3 years ago

Read 2 more answers

I need ideas for what to build because I have some spare wood.

Misha Larkins [42]

Answer:

small guitar with no strings?

Explanation:

it would be fun to make i think

6 0

3 years ago

Technician A says automotive gasoline engines run on the 2 stroke principal. Technician B says Diesel engine hace less compressi

d1i1m1o1n [39]

Answer:

both are incorect

Explanation:

2 stroke principal is a mix of gasoline and engine oil a normal gasoline engine does not run on 2 stroke fuel

technician B is also wrong Diesel engines generally generate much higher compersion than gasoline engines

3 0

3 years ago

The in-situ dry density of a sand is 1.72Mg/m3. The maximum and minimum drydensities, determined by standard laboratory tests, a

Stells [14]

Answer:

Relative density = 0.7 or 70%

Explanation:

The following information was provided by this question

Pd = 1.72mg/mg³

Pd max = 1.81 mg/mg³

Pd min = 1.54 mg/mg³

We substitute into the formula. This formula is contained in the attachment.

[(1/1.54)-(1/1.72)]/[1/1.54 - 1/1.81]

= 0.649350 - 0.581395 / 0.649350 - 0.552486

= 0.067955/0.096864

= 0.7015

= 0.7

The relative density is Therefore 0.7 or 70% when converted to percentage

8 0

3 years ago