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UNO [17]
3 years ago
11

Which of the following is part of the highway

Engineering
2 answers:
kap26 [50]3 years ago
8 0
D) All of these
Because I mean u have to have all of these ya know
kirill [66]3 years ago
4 0

Answer:

D all of these

Explanation: It is all of these because you need a vehicle to be transported, the vehicle needs to have control by a human which are people, and roadways are needed to drive on.

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g A heat exchanger is designed to is to heat 2,500 kg/h of water from 15 to 80 °C by engine oil. The configuration of the heat e
sergey [27]

Answer:

See explaination

Explanation:

Please kindly check attachment for the step by step solution of the given problem.

The attached file gave a detailed solution of the problem.

8 0
3 years ago
A function is different from a procedure because a functiondoes not contain a set of instructions.can have only a limited number
777dan777 [17]

Answer: A function returns a value and a procedure just executes commands.

Explanation:

6 0
2 years ago
Read 2 more answers
A steady, incompressible, two-dimensional velocity field is given by the following components in the x-y plane: u=1.85+2.05x+0.6
amm1812

1) a_x=4.287+2.772x\\a_y=-5.579+2.772y

2) 8.418

Explanation:

1)

The two components of the velocity field in x and y for the field in this problem are:

u=1.85+2.05x+0.656y

v=0.754-2.18x-2.05y

The x-component and y-component of the acceleration field can be found using the following equations:

a_x=\frac{du}{dt}+u\frac{du}{dx}+v\frac{du}{dy}

a_y=\frac{dv}{dt}+u\frac{dv}{dx}+v\frac{dv}{dy}

The derivatives in this problem are:

\frac{du}{dt}=0

\frac{dv}{dt}=0

\frac{du}{dx}=2.05

\frac{du}{dy}=0.656

\frac{dv}{dx}=-2.18

\frac{dv}{dy}=-2.05

Substituting, we find:

a_x=0+(1.85+2.05x+0.656y)(2.05)+(0.754-2.18x-2.05y)(0.656)=\\a_x=4.287+2.772x

And

a_y=0+(1.85+2.05x+0.656y)(-2.18)+(0.754-2.18x-2.05y)(-2.05)=\\a_y=-5.579+2.772y

2)

In this part of the problem, we want to find the acceleration at the point

(x,y) = (-1,5)

So we have

x = -1

y = 5

First of all, we substitute these values of x and y into the expression for the components of the acceleration field:

a_x=4.287+2.772x\\a_y=-5.579+2.772y

And so we find:

a_x=4.287+2.772(-1)=1.515\\a_y=-5.579+2.772(5)=8.281

And finally, we find the magnitude of the acceleration simply by applying Pythagorean's theorem:

a=\sqrt{a_x^2+a_y^2}=\sqrt{1.515^2+8.281^2}=8.418

4 0
3 years ago
Is annealed polycrystalline copper a material that work hardens significantly or a material that exhibits a low work-hardening r
Olegator [25]

Those that harden under strain, such as the aluminum-magnesium alloys used in beverage cans and the copper-zinc alloy, brass, used for cartridges, which show more strain hardening than pure copper or aluminum, respectively.

When a material is deformed under a substantial amount of strain, strain hardening is seen as a strengthening process. Lamellar crystals and chain molecule orientation on a vast scale are the culprits. When plastic materials are stretched past their yield point, this phenomena is frequently seen. When a metal is stretched past its yield point, strain hardening occurs. The metal appears to get stronger and harder to deform as more stress is needed to cause additional plastic deformation. Strain hardening is directly related to fatigue.

Learn more about strain hardening here-

brainly.com/question/15058191

#SPJ4

6 0
1 year ago
An engineers scale is generally used to _______.
Bumek [7]
Measure scale on technical drawings.
7 0
3 years ago
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