Force P is 11304 N and normal stress is 400 N/mm²
<u>Explanation:</u>
Given-
Length, l = 9 m = 9000 mm
Diameter, d = 6 mm
Radius, r = 3 mm
Stretched length, Δl= 18 mm
Modulus of elasticity, E = 200 GPa = 200 X 10³MPa
Force, P = ?
According to Hooke's law,
Stress is directly proportional to strain.
So,
σ ∝ ε
σ = E ε
Where, E is the modulus of elasticity
We know,
ε = Δl / l
So,
σ = E X Δl/l
σ =
We know,
σ = P/A
And A = π (r)²
σ = P / π (r)²
Therefore, Force P is 11304 N and normal stress is 400 N/mm²
Answer: Thx for points...
Explanation:
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Answer:
A. Forces that act perpendicular to the surface and pull an object apart exert a tensile stress on the object.
Explanation:
Tensile stress is referred as a deforming force, in which force acts perpendicular to the surface and pull an object apart, attempting to elongate it.
The tensile stress is a type of normal stress, in which a perpendicular force creates the stress to an object’s surface.
Hence, the correct option is "A."
Answer:
The answer is "Option e".
Explanation:
Given value:
Answer:
Throughout the clarification section elsewhere here, the definition of the concern is mentioned.
Explanation:
- The stress-strain curve provides designers with a long list of critical parameters that are needed for utility development. Including capacity, longevity, elasticity, apparent viscosity, tension electricity, resilience, as well as flexural strength, a load-pressure assignment gave us several mechanical households at a certain point of operation. It also assists in manufacturing.
- During which the overarching force can inform us about the maximum energy either workload the substance will experience, which could also be inferred within the action of the stress-strain. The dynamic properties can be seen by pre maximum activity because it will be before even the maximum yield intensity as well as the posted maximum would display plastic behavior however after the peak becomes achieved, the natural frequencies continue to decline.
