For two variables in a direct proportion, what is the result of doubling one variable?

7. Which of the following compound is the most soluble in CC14? C. NH3 A. HF B. NaCl D. C10H22

Mashutka [201]

C10H22 is a compound which is the most soluble in CC14 because both are non-polar in nature.

<h3>Why polar solute soluble in polar solvent?</h3>

We know that like dissolve like which means that polar solutes only dissolve in polar solvent while on the other hand, non-polar solutes only dissolve in non-polar solvent.

So we can conclude that C10H22 is a compound which is the most soluble in CC14 because both are non-polar in nature.

Learn more about soluble here: brainly.com/question/23946616

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4 0

3 years ago

Given that the freezing point depression constant for water is 1.86°c kg/mol, calculate the change in freezing point for a 0.907

melamori03 [73]

Answer : The correct answer for change in freezing point = 1.69 ° C

Freezing point depression :

It is defined as depression in freezing point of solvent when volatile or non volatile solute is added .

SO when any solute is added freezing point of solution is less than freezing point of pure solvent . This depression in freezing point is directly proportional to molal concentration of solute .

It can be expressed as :

ΔTf = Freezing point of pure solvent - freezing point of solution = i* kf * m

Where : ΔTf = change in freezing point (°C)

i = Von't Hoff factor

kf =molal freezing point depression constant of solvent. $\frac{^0 C}{m}$

m = molality of solute (m or $\frac{mol}{Kg}$ )

Given : kf = 1.86 $\frac{^0 C*Kg}{mol}$

m = 0.907 $\frac{mol}{Kg}$ )

Von't Hoff factor for non volatile solute is always = 1 .Since the sugar is non volatile solute , so i = 1

Plugging value in expression :

ΔTf = 1* 1.86 $\frac{^0 C*Kg}{mol}$ * 0.907 $\frac{mol}{Kg}$ )

ΔTf = 1.69 ° C

Hence change in freezing point = 1.69 °C

5 0

3 years ago

Describe four effects that radiation can have on the human body.

Alinara [238K]

Answer:

There are many effects of radiation to the human body. (if you watch the 100, you'll see what happens)

Exposure to very high levels of radiation, such as being close to an atomic blast, can cause acute health effects such as

1. weakness

a/ fatigue,

b/ fainting,

c/ confusion.

2.Bleeding from the nose,

a/ mouth,

b/ gums,

c/ rectum

3. Bruising,

a/ skin burns,

b/ open sores on the skin,

c/ sloughing of skin.

4. Dehydration.

5. Diarrhea, bloody stool.

6. Fever.

7. Hair loss.

8. Inflammation of ex

5 0

3 years ago

Cora, an electrician, wraps a copper wire with a thick plastic coating. What is she most likely trying to do? keep the electric

Alekssandra [29.7K]

Answer: keep a current from passing out of the wire

Explanation: plastic is an insulator and will not conduct electricity

3 0

4 years ago

Read 2 more answers

You calculate the Wilson equation parameters for the ethanol (1) 1 1-propanol (2) system at 258C and find they are L12 5 0.7 and

Gala2k [10]

Here is the correct question.

You calculate the Wilson equation parameters for the ethanol (1) +1 - propanol (2) system at 25° C and find they are ∧₁₂ = 0.7 and ∧₂₁ = 1.1 . Estimate the value of parameters at 50° C

Answer:

the values of the parameters at 50° C are 0.766 and 1.047

Explanation:

From "critical point , enthalpy of phase change and liquid molar volume " the liquid molar volume (v) of ethanol and 1 - propanol is represented as follows:

Compound Liquid molar volume (cm³/mol)

Ethanol (1) 58.68

1 - propanol (2) 75.14

To calculate the temperature dependent parameters of the Wilson equation ∧₁₂.

∧₁₂ = $\frac{V_2}{V_1} \ exp \ (\frac{-a_{12}/R}{T} )$ ------------ equation (1)