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victus00 [196]
3 years ago
7

How to graph a inequality

Mathematics
1 answer:
4vir4ik [10]3 years ago
8 0
Graph it like you would a normal equation except if it's not "equal to" it's a dashed line instead of solid line. Then shade the appropriate area on the graph,
for example..
y > 2x +1
is graphed as a dashed line y = 2x +1 since it doesn't actually equal y.
y is greater than the line/equation so the area above is shaded where y is bigger
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OT bisects ∠DOG. Find the measure of ∠DOG if ∠DOT = 4x + 4 and ∠TOG = 5x – 3
g100num [7]

Answer:

\huge\boxed{64^o}

Step-by-step explanation:

If OT is bisects ∠DOG, then m∠DOT = m∠TOG. Therefore

4x+4=5x-3    |<em>subtract 4 from both sides</em>

<em />4x+4-4=5x-3-4\\\\4x=5x-7<em>|subtract 5x from both sides</em>

<em />4x-5x=5x-5x-7\\\\-x=-7<em>|change the signs</em>

<em />x=7<em />

Calculate the measure of ∠DOG

m∠DOG = 2(m∠DOT)

m\angle DOG=2(4\cdot7+4)=2(28+4)=2(32)=64

6 0
3 years ago
Find the slope of the line that<br> passes through the following<br> points. (0,0), (-2,-4)
Ann [662]

Answer:

m=2

Step-by-step explanation:

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5 0
3 years ago
Read 2 more answers
Solve the following equation for <br><br><br> G:2 (g-h) = b+4
Klio2033 [76]

If the equation 2(g - h) = b + 4 is solved for g. Then the value of g will be b/2 + h + 2.

<h3>What is the solution of the equation?</h3>

A combination of equations solution is a collection of values x, y, z, etc. that enable all of the calculations to true at the same time.

The equation is given below.

2(g - h) = b + 4

Then solve the equation for the value of g. Then we have

2(g - h) = b + 4

   g - h = b/2 + 2

        g = h + b/2 + 2

More about the solution of the equation link is given below.

brainly.com/question/545403

#SPJ1

3 0
2 years ago
10) xc = rd , for x<br><br> Help plz
ExtremeBDS [4]

Answer:

x = rd/c

Step-by-step explanation:

xc = rd

xc/c = rd/c

x = rd/c

8 0
3 years ago
Correct/best answer will get brainliest!
vodka [1.7K]
The answer would be b.100 because its clearly not a right triangle
6 0
3 years ago
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