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Ganezh [65]
3 years ago
6

A golf ball traveling 3m/s to the right collides in a head-on collision with a stationary bowling ball in a friction-free enviro

nment. If the collision is almost perfectly elastic, the speed of the golf ball immediately after the collision is a) slightly greater b) much less than 3 m/s c) equal to 3 m/s d) slightly less than 3 m/s
Physics
1 answer:
Vladimir79 [104]3 years ago
3 0

Answer: equal to 3 m/s

Explanation:

Speed of golf ball will be equal to 3 m/s because in Perfect Elastic Collision Energy is conserved .

So speed of golf ball will be same in order to Satisfy

Initial Kinetic Energy =Final Kinetic Energy

Considering Bowling ball remains at rest after collision other wise some energy will also be acquired by bowling ball which automatically decreases the amount of Kinetic Energy of golf ball resulting its speed to decrease by some extent.  

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The temperature of the cosmic background radiation is measured to be 2.7 k. What is the wavelength of the peak in the spectral d
KATRIN_1 [288]

Answer:

1.07\cdot 10^{-3} m

Explanation:

The peak wavelength of the spectral distribution can be found by using Wien's displacement law:

\lambda=\frac{b}{T}

where

b=2.898\cdot 10^{-3} m\cdot K is Wien's displacement constant

T is the absolute temperature

For the cosmic background radiation, the temperature is

T = 2.7 K

So, the corresponding peak wavelength is

\lambda=\frac{2.898\cdot 10^{-3} m\cdot K}{2.7 K}=1.07\cdot 10^{-3} m

7 0
3 years ago
A sprinter starts from rest and reaches a speed of 15 m/s in 4.25 s. Find his acceleration
kakasveta [241]

Answer:

a=3.53 m/s^2

Explanation:

Vo=0 m/s (because he is not moving at the start)

V1=15 m/s

t= 4.25 s

a = (V1-Vo) / t = 15/4.25 = 3.53 m/s^2

5 0
3 years ago
NEEED HELP!!!
Amanda [17]

Answer:

The correct choice is A. Yes, the more exercise the better.

5 0
2 years ago
As you may well know, placing metal objects inside a microwave oven can generate sparks. Two of your friends are arguing over th
Fofino [41]

Answer:

5.04\cdot 10^8 A

Explanation:

The work function of the metal corresponds to the minimum energy needed to extract a photoelectron from the metal. In this case, it is:

\phi = 3.950\cdot 10^{-19}J

So, the energy of the incoming photon hitting on the metal must be at least equal to this value.

The energy of a photon is given by

E=\frac{hc}{\lambda}

where

h is the Planck's constant

c is the speed of light

\lambda is the wavelength of the photon

Using E=\phi and solving for \lambda, we find the maximum wavelength of the radiation that will eject electrons from the metal:

\lambda=\frac{hc}{E}=\frac{(6.63\cdot 10^{-34} Js)(3\cdot 10^8 m/s)}{3.950\cdot 10^{-19} J}=5.04\cdot 10^{-7}m

And since

1 angstrom = 10^{-15}m

The wavelength in angstroms is

\lambda=\frac{5.04\cdot 10^{-7} m}{10^{-15} m/A}=5.04\cdot 10^8 A

3 0
3 years ago
Please help I literally don’t understand
Veseljchak [2.6K]

Answer:

A= 2

B=3

C=4

D=5

E=7

F=8

H=12

7 0
3 years ago
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