Answer:
Mass of Sucrose in given Solution is 401.8158 grams.
Explanation:
Given,
Molarity of Sucrose Solution = 0.758 M.
Volume of Sucrose Solution(V) = 1.55 L.
To find the mass of Sucrose in the solution, we need to find the number of moles of Sucrose present in the given solution 0f 0.758 M.
c = 0.758 M
number of moles can be calculated using
n = c*V
n= 0.758*1.55 = 1.1749 moles
Then to convert no, of moles to mass, we can use the formula,
number of moles(n) = Mass(m)/Molar Mass(M)
The Molar mass of Sucrose C₁₂H₂₂O₁₁ is
Mass of Carbon Sucrose = 12*12 = 144 grams
Mass of Hydogen in Sucrose = 1*22 = 22 grams
Mass of Oxygen in Sucrose = 16*11 = 176 grams
Molar mass of Sucrose = 144 + 22 +176 = 342 grams.
Substituting the values in the formula,
number of moles(n) = Mass(m)/Molar Mass(M)
we get,
1.1749 = (m)/342 => m = 1.1749 *342 = 401.8158 grams.
