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tino4ka555 [31]
3 years ago
12

To explain the photoelectric effect, Albert Einstein linked the photoelectric effect to an idea from which scientist?

Chemistry
2 answers:
Georgia [21]3 years ago
7 0
Max planck
hope i helped!
const2013 [10]3 years ago
6 0

Answer:

Max Planck

if you get this answer usefull

so pls mark me as a brainlist

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DNA and RNA is your answer

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A chemistry student needs 60.0 ml of ethanolamine for an experiment. By consulting the CRC Handbook of Chemistry and Physics, th
BARSIC [14]

Answer:

The student should weigh out 61.2g of ethanolamine [6.12 * 10]

Explanation:

In this question, we are expected to calculate the mass of ethanolamine needed to make 60.0ml of it given that the density of the ethanolamine in question is 1.02g/cm^3

Mathematically, it has been shown that mass = density * volume

Hence, by multiplying the density by the volume, we get the mass.

Now, from the question we can see that we have the values for the density and the volume. We now need to get the mass.

Since cm^3 is same as ml, we need not perform any conversion.

Hence, the needed mass is:

60 * 1.02 = 61.2g

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4 years ago
How does the strength of a metallic bond compared to other types of bonds?
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While metallic bonds have the strong electrostatic force of attractions between the cation or atoms and the delocalized electrons in the geometrical arrangement of the two metals. ... Metallic bonds are malleable and ductile, while covalent bonds and ionic bonds non-malleable and non-ductile.

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3 years ago
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Two billiard balls having masses of 0.2 kg and 0.15kg approach each other. The first ball having a velocity of 2m/s hit the seco
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Answer: The velocity of the first ball is 0.875 m/s if the second ball travels at 1.5 m/s after collision.

Explanation:

Given: m_{1} = 0.2 kg,      m_{2} = 0.15 kg

v_{1} = 2 m/s,    v_{2} = 0 m/s,      v'_{1} = ?,          v'_{2} = 1.5 m/s

Formula used is as follows.

m_{1}v_{1} + m_{2}v_{2} = m_{1}v'_{1} + m_{2}v'_{2}

where,

v = velocity before collision

v' = velocity after collision

Substitute the values into above formula as follows.

m_{1}v_{1} + m_{2}v_{2} = m_{1}v'_{1} + m_{2}v'_{2}\\0.2 kg \times 2 m/s + 0.15 kg \times 0 m/s = 0.2 kg \times v'_{1} + 0.15 kg \times 1.5 m/s\\0.4 kg m/s + 0 = 0.2v'_{1} + 0.225 kg m/s\\0.2v'_{1} kg = 0.175 kg m/s\\v'_{1} = \frac{0.175 kg m/s}{0.2 kg}\\= 0.875 m/s

Thus, we can conclude that the velocity of the first ball is 0.875 m/s if the second ball travels at 1.5 m/s after collision.

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4 years ago
If the statement is true, select True. If it is false, select False.
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Answer:

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Explanation:

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