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allochka39001 [22]
3 years ago
13

How many gallons in 2 L bottle

Chemistry
1 answer:
zepelin [54]3 years ago
4 0
0.528 us liquid gallon
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Splitting nuclei is called __________ and joining nuclei is called _________.
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Sodium phosphate and calcium chloride react to form sodium chloride and calcium phosphate. If you have 379.4 grams of calcium ch
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Answer:- A. 353.5 g

Solution:- The balanced equation is:

2Na_3PO_4(aq)+3CaCl_2(aq)\rightarrow 6NaCl(aq)+Ca_3(PO_4)_2(s)

From this equation, there is 3:1 mol ratio between calcium chloride and calcium phosphate.

Grams of calcium chloride are converted to moles and these moles are multiplied by the mol ratio to get the moles of calcium phosphate. Finally the moles are multiplied by molar mass to get the grams of calcium phosphate.

Molar mass of CaCl_2 = 40.078+2(35.45) = 110.978 g per mol

Molar mass of Ca_3(PO_4)_2 = 3(40.078)+2(30.974)+8(16.00)

= 120.234+61.948+128.00 = 310.182 g per mol

let's make the set up using dimensional analysis.

379.4gCaCl_2(\frac{1molCaCl_2}{110.978gCaCl_2})(\frac{1molCa_3(PO_4)_2}{3molCaCl_2})(\frac{310.182gCa_3(PO_4)_2}{1molCa_3(PO_4)_2})

= 353.5gCa_3(PO_4)_2

Hence, 353.5 g of calcium phosphate will form and so the correct option is A.

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4 years ago
What changes in space result from the death of massive stars?
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Whenever the fuel is being used up, a star explodes and the energy leakage from a star's core ceases.

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The RNA and DNA backbone differ because the DNA sugar is missing what element?
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4 0
3 years ago
To 100.0 g water at 25.00 ºc in a well-insulated container is added a block of aluminum initially at 100.0 ºc. the temperature o
11111nata11111 [884]
When the amount of heat gained = the amount of heat loss

so, M*C*ΔTloses = M*C* ΔT gained

when here the water is gained heat as the Ti = 25°C and Tf= 28°C so it gains more heat.

∴( M * C * ΔT )W = (M*C*ΔT) Al

when Mw is the mass of water = 100 g 

and C the specific heat capacity of water = 4.18

and ΔT the change in temperature for water= 28-25 = 3 ° C

and ΔT the change in temperature for Al = 100-28= 72°C

and M Al is the mass of Al block

C is the specific heat capacity of the block = 0.9 

so by substitution:

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4 0
3 years ago
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