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Rus_ich [418]
3 years ago
13

if you throw a heavy log into the fireplace, after it burns you are left with some ash. the ash has a mass much less then the ma

ss of the original log. this seems to go against the law of conservation of mass. please explain what we are forgetting.
Chemistry
1 answer:
Harrizon [31]3 years ago
8 0

Answer: ?

Explanation:

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What is the pressure of a sample of gas at a volume of .335 L if it occupies 1700 mL at 850 mm Hg?
dangina [55]

Answer:

Pressure = 4313.43mmHg

Explanation:

P1 = ?

V1 = 0.335L

V2 = 1700mL =1700*10^-3L = 1.7L

P2 = 850mmhg

From Boyle's law, the volume of a fixed mass of gas is inversely proportional to its pressure provided that temperature remains constant.

P = k / v

K = pv. P1V1 = P2V2 = P3V3 =........=PnVn

P1V1 = P2V2

Solve for P1,

P1 = (P2*V2) / V1

P1 = (850 * 1.7) / 0.335

P1 = 4313.43mmHg

The pressure of the gas was 4313.43mmHg

7 0
3 years ago
Under identical conditions of temperature and pressure, which of the following gasses is the densest: Ne, CO2, or Cl2?
Tanzania [10]
Cl2=3.17g/L
Ne=.901g/L
CO2=1.96g/l
 therefore Cl2 is the densest gas under the given conditions.
7 0
3 years ago
A gas occupies a volume of 31.0 ml at 19.0°C. If the gas temperature rises to 38.0°C at constant pressure. Calculate the new vol
Alik [6]

Answer:

The correct answer is 0.0033 L (33.0 mL)

Explanation:

We uses the Charles's law which describes the changes in the volume (V) of a gas and its temperature in Kelvin (T) at constant pressure. The mathematical expression is the following:

V₁/T₁ = V₂/T₂

We have the following data:

V₁= 31.0 mL = 0.0031 L

T₁= 19.0°C = 292 K

T₂= 38.0°C = 311 K

V₂= ?

We calculate V₂ from the mathematical expression, as follows:

V₂= V₁/T₁ x T₂ = 0.0031 L/(292 K) x 311 K = 0.0033 L

5 0
2 years ago
QUESTION 11
Iteru [2.4K]
I actually don’t know but good question
6 0
3 years ago
Using the idea that reactions occur as a result of collisions between particles, explain why reaction rates depend on the temper
PIT_PIT [208]

Increasing temperatures in a reaction increases the kinetic energy of the reactant molecules. This causes them to move fast and hence collide with a higher frequency. The higher the rate of collision between the molecules, the faster the reaction.

6 0
3 years ago
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