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Rus_ich [418]
3 years ago
13

if you throw a heavy log into the fireplace, after it burns you are left with some ash. the ash has a mass much less then the ma

ss of the original log. this seems to go against the law of conservation of mass. please explain what we are forgetting.
Chemistry
1 answer:
Harrizon [31]3 years ago
8 0

Answer: ?

Explanation:

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Which of the following is an example of a liquid and gas mixture? *
Stolb23 [73]

Answer:

Carbonated Water

Explanation:

Carbonated water is a mixture of carbon dioxide gas and water.

7 0
3 years ago
Count the total number of atoms in sio2:
grigory [225]
Atoms are the basic units of matter and the defining structure of elements. We count the number of atoms by the total number of elements present in the compound. In this case, we have 1 atom of Si and 2 atoms of oxygen which would have 3 total number of atoms.
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3 years ago
What is the current produced when a 12-Volt battery encounters a resistance of 20 Ohms?
Verdich [7]

Answer:

Explanation:

V = IR

I = V/R

I = (12V)/(20Ω)

I = 0.6 A

4 0
3 years ago
How long would it take Jesse, with an acceleration of -2.50 m/s², to bring his bicycle, with an initial velocity of 13.5 m/s, to
lbvjy [14]

Answer:

i am so sorry. i do not have a answer but i am trying to find questioms i can answer

6 0
3 years ago
When 229.0 J of energy is supplied as heat to 3.00 mol of Ar(g) at constant pressure the temperature of the sample increases by
bazaltina [42]

Answer:

The molar heat capacity at constant volume is 21.62 JK⁻¹mol⁻¹

The molar heat capacity at constant pressure is 29.93 JK⁻¹mol⁻¹

Explanation:

We can calculate the molar heat capacity at constant pressure from

C_{p,m} = \frac{C_{p} }{n}

Where C_{p,m} is the molar heat capacity at constant pressure

{C_{p} } is the heat capacity at constant pressure

and n is the number of moles

Also {C_{p} } is given by

{C_{p} } = \frac{\Delta H}{\Delta T}

Hence,

C_{p,m} = \frac{C_{p} }{n} becomes

C_{p,m} = \frac{\Delta H }{n \Delta T}

From the question,

\Delta H = 229.0 J

n = 3.00 mol

\Delta T = 2.55 K

Hence,

C_{p,m} = \frac{\Delta H }{n \Delta T} becomes

C_{p,m} = \frac{229.0}{(3.00) (2.55)}

C_{p,m} = 29.93 JK⁻¹mol⁻¹

This is the molar heat capacity at constant pressure

For, the molar heat capacity at constant volume,

From the formula

C_{p,m} = C_{v,m} + R

Where C_{v,m} is the molar heat capacity at constant volume

and R is the gas constant (R = 8.314 JK⁻¹mol⁻¹)

Then,

C_{v,m} = C_{p,m}  - R

C_{v,m} = 29.93 - 8.314

C_{v,m} = 21.62 JK⁻¹mol⁻¹

This is the molar heat capacity at constant volume

5 0
3 years ago
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