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3 years ago

5 less than 3 times a number is 7. How would I write this as an equation

2 answers:

5 0

You want to break this down.

“5 less than” means you’ll subtract 5 from something.

That something is “3 times a number.” “3 times a number” means 3•x or 3x, since we’ll use x for that unknown number.

So, “5 less than 3 times a number” means “subtract 5 from 3x”: 3x-5

“Is” means “equals”. So 3x-5= something.

7, well, that’s 7.

So “5 less than 3 times a number is 7” means ”subtract 5 from 3x and set that equal to 7.”

3x-5=7

ValentinkaMS [17]3 years ago

3 0

Answer:

The equation would be 5-3x=7

Step-by-step explanation:

5 less than indicates subtraction, and 3 times a number indicates both values being multiplied with each other, so it's 3x. Hope that helped.

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3 years ago

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Given:

In the given circle O, BC is diameter, OA is radius, DC is a chord parallel to chord BA and $m\angle BCD=30^\circ$ .

To find:

The $m\angle AOB$ .

Solution:

If a transversal line intersect two parallel lines, then the alternate interior angles are congruent.

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In triangle AOB, OA and OB are radii of the circle O. It means OA=OB and triangle AOB is an isosceles triangle.

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Step-by-step explanation:

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Answer:

See below

Step-by-step explanation:

It has something to do with the Weierstrass substitution, where we have

$\int\, f(\sin(x), \cos(x))dx = \int\, \dfrac{2}{1+t^2}f\left(\dfrac{2t}{1+t^2}, \dfrac{1-t^2}{1+t^2} \right)dt$

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$\tan(2x)= \dfrac{2\tan(x)}{1-\tan^2(x)}$

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$\tan\left(2 \cdot\dfrac{x}{2}\right)= \dfrac{2\tan(x/2)}{1-\tan^2(x/2)} = \tan(x)=\dfrac{2t}{1-t^2}$

Once the double angle identity for sine is

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Thus,

$\cos(x)= \left(\dfrac{1}{\sqrt{1 + t^2}}\right)^2- \left(\dfrac{t}{\sqrt{1 + t^2}}\right)^2 = \dfrac{1}{t^2+1}-\dfrac{t^2}{t^2+1} =\dfrac{1-t^2}{1+t^2}$