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balu736 [363]
3 years ago
14

64×15=32×30 true or false

Mathematics
2 answers:
Fofino [41]3 years ago
8 0
64x15=960 and 32x30=960
so therefore it is true
Dima020 [189]3 years ago
4 0

\large \mathfrak{Solution : }

Yes, it's true because the value of LHS = RHS if we solve it .

  • 64 \times 15 = 32 \times 30

  • 90 = 90
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EXPLAIN
zvonat [6]

Answer:

50,000? This is my answer sorry if wrong

Step-by-step explanation:

4 0
2 years ago
A jar made of 3/16-inch-thick glass has an inside radius of 3.00 inches and a total height of 6.00 inches (including the bottom
Nady [450]

Answer:

a) 0.012ft³

b)2.09 lb

c)0.791 lb

d) 0.012ft³

e) 6 inches

Step-by-step explanation:

a) To determine the volume of the shell of the jar we must determine the volume of the hollow cylinder:

V=3.1416\cdot{h}\cdot{(R^2-r^2)

Where r is the inside radius and R the outer radius.

V=3.1416\cdot{6}\cdot{(3.1875^2-3^2)=21.87

convert to cubic ft:

=21.87\cdot{0.0005787}=0.01266

The volume of the glass shell is 0.012 ft³

b) The weight of the cylinder can be determined because we have the volume and the density. Weight is defined as the product of volume and density:

M=p\cdot{v}=165\cdot{0.01266}=2.09

The weight of the jar is 2.09 lb

c) The displacement of water is just the density of water mutliplied by the volume of the jar:#

=0.01266\cdot{62.5}=0.79

0.791 lb of water will be displaced.

d) The volume of the water displaced is:

[tex]=0.791/62.5=0.01266

e) The jar will be fully submerged because the density of the jar is larger than water.

5 0
3 years ago
A 6m ladder leans against a wall. The bottom of the ladder is 1.3m from the wall at time =0sec and slides away from the wall at
icang [17]

Answer:

- 0.100

Step-by-step explanation:

Length of the ladder,  H = 6 m

Distance at the bottom from the wall, B = 1.3 m

Let the distance of top of the ladder from the bottom at the wall is P

Thus,

from  Pythagoras theorem,

B² + P² = H²    .

or

B² + P² = 6²          ..............(1)      [Since length of the ladder remains constant]

at B = 1.3 m

1.3² + P² = 6²

or

P² = 36 - 1.69

or

P² = 34.31

or

P = 5.857

Now,

differentiating (1)

2B(\frac{dB}{dt})+2P(\frac{dP}{dt})=0

at t = 2 seconds

change in B = 0.3 × 2= 0.6 ft

Thus,

at 2 seconds

B = 1.3 + 0.6 = 1.9 m

therefore,

1.9² + P² = 6²

or

P = 5.69 m

on substituting the given values,

2(1.9)(0.3) + 2(5.69) × (\frac{dP}{dt}) = 0

or

1.14 + 11.38 × (\frac{dP}{dt}) = 0

or

11.38 × (\frac{dP}{dt}) = - 1.14

or

(\frac{dP}{dt}) = - 0.100

here, negative sign means that the velocity is in downward direction as upward is positive

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3 years ago
Wat is the value of 6 in 90.16
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