The current intensity is defined as the amount of charge Q that passes through a certain point of an electrical wire in a time interval of

:

In our problem, the current intensity is

while the amount of charge that passes a certain point of the wire is

If we re-arrange the previous equation:

we can find the time needed for this amount of charge to pass through a point of the wire:
Answer:
4 seconds
Explanation:
Given:
v₀ = 0 m/s
v = 20 m/s
a = 5 m/s²
Find: t
v = at + v₀
20 m/s = (5 m/s²) t + 0 m/s
t = 4 s
Answer:
Option D) -0.0707
Explanation:
We are given the following in the question:
Population mean, μ = 45 mp
Sample mean,
= 44.9
Sample size, n = 50
Sample standard deviation, s = 10
Formula:
Putting all the values, we have
Thus, the test statistic is
Option D) -0.0707
<h2>
Law 1:</h2><h3>An object already in motion stays in motion, unless acted upon by a force.</h3><h3 /><h2>Law 2:</h2><h3>

</h3><h3>f = forces on an object</h3><h3>m = mass of that object</h3><h3>a = acceleration of that object</h3><h3 /><h2>Law 3:</h2><h3>Everything has an equal and opposite reaction.</h3><h3 /><h3>Hope this helps!</h3>
Answer:
-72.0°C
Explanation:
PV = nRT
Since n, number of moles, is constant:
PV / T = PV / T
(4.65×10⁶ Pa) V / (21 + 273.15) K = (1.06×10⁶ Pa) (3V) / T
T = 201.16 K
T = -72.0°C