Total distance = 36500 m
The average velocity = 19.73 m/s
<h3>Further explanation</h3>Given
vo=initial velocity=0(from rest)
a=acceleration= 1 m/s²
t₁ = 20 s
t₂ = 0.5 hr = 1800 s
t₃= 30 s
Required
Total distance
Solution
State 1 : acceleration
State 2 : constant speed
State 3 : deceleration
Total distance : state 1+ state 2+state 3
the average velocity = total distance : total time
we know that center of mass is given as
r = (m₁ + m₂
)/(m₁ + m₂)
taking derivative both side relative to "t"
dr/dt = (m₁ d/dt + m₂ d
/dt)/(m₁ + m₂)
v = (m₁ + m₂
)/(m₁ + m₂)
taking derivative again relative to "t" both side
dv/dt = (m₁ d/dt + m₂ d
/dt)/(m₁ + m₂)
a= (m₁ + m₂
)/(m₁ + m₂)
Answer:
Explanation:
Given
For first case
launch angle
at highest point
For second case
at highest Point velocity is
as there is no acceleration in x direction therefore horizontal velocity is same