Answer:
The partial pressure of argon in the flask = 71.326 K pa
Explanation:
Volume off the flask = 0.001 
Mass of the gas = 1.15 gm = 0.00115 kg
Temperature = 25 ° c = 298 K
Gas constant for Argon R = 208.13 
From ideal gas equation P V = m RT
⇒ P = 
Put all the values in above formula we get
⇒ P = 
× 208.13 × 298
⇒ P = 71.326 K pa
Therefore, the partial pressure of argon in the flask = 71.326 K pa
Answer:
Explanation:E=hc¯ν=hcλ [Where h = Planck's constant, c = velocity of electromagnetic radiation(light) and lambda = wavelength.] So, just substitute every needed value. =1.29077⋅10−18 Joules
Answer:
The answer to your question is: 70.7 %
Explanation:
Equation
Xe + 2F₂ ⇒ XeF₄
limiting reactant = Xe
Xe is the limiting reactant because the ratio is:
theoretical = 131/ 76 = 1.72 g
experimental ratio = 130/100 = 1.3 the amount of F increased.
131.3 g of Xe ------------------ 207 g of XeF₄
130 g of Xe ------------------- x
x = (130 x 207) / 131.3
x = 205 g of XeF₄
% yield = 145 / 205 x 100
% yield = 70.7
Answer:
There are 6 hydrogen atoms.
Explanation:
The formula for an alkyne that has only one triple bond is as follows:
Where n is any natural number greater than 2.
For this problem, n=4. This would mean the formula is:
Thus
Thus the answer is 6, there are 6 hydrogen atoms.
We are asked for the energy emitted by a photon using the wavelength given. In this case, we use the planck relation that correlates energy and wavelength using Planck's constant and speed of light as constant of proportionality. The formula is E = hc / w where h is equal to 6.626 x10-34 Js and c is equal to 3 x10 8 m/s. E then is equal to 1.55 x10-24 J
