Question

SOMEONE HELP PLS ILL GIVE BRAINLIEST AND 19 PT

Answer 1

Sample left = 6.25 g

The percentage = 6.25%

Further explanation

Given

t1/2 = half-life = 3.8 days

t = decay time = 15.2 days

No = initial sample = 100 g

Required

Nt = final sample left

The percentage

Solution

General formulas used in decay:  

$\large{\boxed{\bold{N_t=N_0(\dfrac{1}{2})^{t/t\frac{1}{2} }}}$

Input the value :

$\tt N_t=100.\dfrac{1}{2}^{15.2/3.8}\\\\N_t=100.\dfrac{1}{2}^4\\\\N_t=6.25~g$

The percentage : Nt/No

6.25 : 100 = 6.25%