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Sedaia [141]
3 years ago
15

SOMEONE HELP PLS ILL GIVE BRAINLIEST AND 19 PT

Chemistry
1 answer:
Ahat [919]3 years ago
5 0

Sample left = 6.25 g

The percentage = 6.25%

<h3>Further explanation</h3>

Given

t1/2 = half-life = 3.8 days

t = decay time = 15.2 days

No = initial sample = 100 g

Required

Nt = final sample left

The percentage

Solution

General formulas used in decay:  

\large{\boxed{\bold{N_t=N_0(\dfrac{1}{2})^{t/t\frac{1}{2} }}}

Input the value :

\tt N_t=100.\dfrac{1}{2}^{15.2/3.8}\\\\N_t=100.\dfrac{1}{2}^4\\\\N_t=6.25~g

The percentage : Nt/No

6.25 : 100 = 6.25%

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A chemist compresses a 1.8 L sample of carbon dioxide gas at 2.4 atm to a final volume of 1.5 L. Assuming the temperature is con
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THE PRESSURE EXERTED BY THE GAS IS THEREFORE 2.88 atm.

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Step 1: Given data

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