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2 years ago

What product(s) forms at the cathode in the electrolysis of an aqueous solution of k2so4?

1 answer:

8 0

Catod(-)
K⁺
2H20 +2e⁻ ---> H2 +2OH⁻

We can also say, that
K⁺ +OH⁻ +H2 = KOH +H2
At the cathode KOH and H2 are formed.

You might be interested in

How many moles are there in 8.50 X 1024 molecules of sodium sulfate, Na2SO3?

il63 [147K]

Answer:

<h2>14.12 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

$n = \frac{N}{L} \\$

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

$n = \frac{8.50 \times {10}^{24} }{6.02 \times {10}^{23} } \\ = 14.119601...$

We have the final answer as

<h3>14.12 moles</h3>

Hope this helps you

3 0

2 years ago

Why do bananas and sprite react chemically?

Alex777 [14]

He Sprite and Banana Challenge consists of eating two bananas and then drinking a liter of Sprite<span>. This causes you to projectile vomit and throw up all over the place!</span>

5 0

3 years ago

Read 2 more answers

What is the relationship between the word pairs in this analogy? dull: boring as amusing: entertaining O A. Synonyms O B. Antony

leva [86]

Answer:

A: Synonyms

Explanation:

Synonyms are two words that have same meaning but are different words (tell me if this works!)

8 0

2 years ago

Read 2 more answers

A 8.00 L tank at 26.9 C is filled with 5.53 g of dinitrogen difluoride gas and 17.3 g of sulfur hexafluoride gas. You can assume

pshichka [43]

Answer:

mole fraction of N_2 O = 0.330

mole of fraction SF_4 = 0.669

PRESSURE OF N_2 O = 39127.053 Pa

pressure of SF_4 = 792126.36

Total pressure = 118253.413 Pa

Explanation:

Given data:

volume of tank 8 L

Weight of dinitrogen difluoride gas 5.53 g

weight of sulphur hexafluoride gas 17.3 g

Amount of $N_2 O = \frac{5.53}{14*2 + 16} = 0.1256 mol$

amount of $SF_4 = \frac{17.3}{32.1 + 19*4} = 0.254 mol$

mole fraction of $N_2 O = \frac{0.1256}{0.1256 + 0.254} = 0.330$

mole of fraction $SF_4 = \frac{0.254}{0.1256 + 0.254} = 0.669$

PV = nRT

P of N_2 O $= \frac{0.1256 *8.31 (273 + 26.9}{0.008} = 39127.053 Pa$

mole of SF_4 $=\frac{0.254 *8.31*(273+26.9)}{.008} = 79126.36 Pa$

Total pressure = 39127.053 + 79126.36 = 118253.413 Pa

6 0

3 years ago

PLEASE HURRY THIS IS TIMED!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

AURORKA [14]

Answer:

if i remember correctly i beleive its A 1.8 x 10^24

but im not for sure also i think you forgot the 24

Explanation:

5 0

3 years ago