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frez [133]
3 years ago
13

Five hundred (500) milliliters of sodium chloride 0.9% is prescribed to be given over 4 hours using a volumetric pump. What's th

e infusion rate in milliliters/hour?
Chemistry
1 answer:
Angelina_Jolie [31]3 years ago
6 0

<u>Given:</u>

Volume of 0.9% NaCl = 500 ml

Time (t) = 4 hrs

<u>To determine:</u>

The infusion rate of NaCl in ml/hr

<u>Explanation:</u>

Based on the information- 500 ml of NaCl is to be given over a time span of 4 hrs

Hence, the volume of NaCl to be administered per hr is:-

= 1 hr * 500 ml/4 hr = 125 ml

Ans: Infusion rate = 125 ml/hr

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Lavoisier is known as the “Father of Modern Chemistry” or the “Father of Chemistry”.

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3 years ago
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"Calculate the number of millimoles in 500 mg of each of the following amino acids: alanine (MW = 89), leucine (131), tryptophan
Cloud [144]

Answer:

- Alanine =  5.61 mmoles

- Leucine = 3.81 mmoles

- Tryptophan = 2.45 mmoles

- Cysteine = 4.13 mmoles

- Glutamic acid = 3.40 mmoles

Explanation:

Mass / Molar mass = Moles

Milimoles = Mol . 1000

500 mg / 1000 = 0.5 g

- Alanine = 0.5 g / 89 g/m → 5.61x10⁻³ moles  . 1000 = 5.61mmoles

- Leucine = 0.5 g / 131 g/m → 3.81 x10⁻³ moles  . 1000 = 3.81 mmoles

- Tryptophan = 0.5 g / 204 g/m →  2.45x10⁻³ moles . 1000 = 2.45 mmoles

- Cysteine = 0.5 g / 121 g/m → 4.13x10⁻³ moles . 1000 = 4.13 mmoles

- Glutamic acid = 0.5 g 147 g/m → 3.40x10⁻³ moles . 1000 =  3.4 mmoles

5 0
3 years ago
Solid strontium chromate, SrCrO4, dissolves into its respective ions at 25°C. Suppose that in a particular solution,
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Answer:

I think it's d but I'm not positive

5 0
3 years ago
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Another term sometimes used for the celsius scale
chubhunter [2.5K]

Answer:

Explanation:

Centigrade

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3 years ago
I really need help pls, will pay anything
Triss [41]

Explanation:

For the first part,

 Reaction equation:

         N₂  +  3H₂   →   2NH₃

Given:

Number of moles of NH₃  = 6 moles

Unknown:

Number of moles of N₂  = ?

Solution:

   N₂  +  3H₂   →   2NH₃;

  From the reaction above, we solve from the known specie to the unknown. Ensure that the equation is balanced;

         2 moles of NH₃ is produced from 1 mole of N₂

        6 moles of NH₃ will be produced from \frac{6}{2}  mole of N₂

                                                                      = 3moles of N₂

The number of moles of N₂ is 3 moles

ii.

Given parameters:

Number of moles of sulfur = 2.4moles

Molar mass of sulfur  = 32.07g/mol

Unknown:

Mass of sulfur  = ?

Solution:

The number of moles of any substance can be found using the expression below;

 Number of moles  = \frac{mass}{molar mass}

  Mass of sulfur  = number of moles of sulfur x molar mass

Insert the parameters and solve;

    Mass of sulfur  = 2.4 x 32.07  = 76.97g

6 0
3 years ago
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