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Goryan [66]
3 years ago
15

Please answer these!

Physics
1 answer:
solong [7]3 years ago
8 0

6. f = 128.62 s^{-1} , T= 0.0077775 s

7. f  = 2.2 * 10^{4} s^{-1}, T = 4.545 * 10^{-5} s

8. 32.64 s^{-1}

9. 3.29 * 10^{14} s^{-1}

Explanation:

Step 1:

6.

For light and sound v = fλ

where v represents the velocity

f represents the frequency

λ represents the wavelength

λ = 2.69 m

v = 346 m/s

f = v/λ = 346/2.69 = 128.62 s^{-1}

Time period is the reciprocal of frequency

T = 1/128.62 = 0.0077775 s

Step 2:

7.

λ = 110 cm = 1.1 m

v = 2.42*10^{4} m/s

f = 2.42*10^{4}/1.1 = 2.2 * 10^{4} s^{-1}

T = 1/(2.2*10^{4}) = 4.545 * 10^{-5} s

Step 3:

8.

λ = 10.6 m

v = 346 m/s

f = v/λ = 346/10.6 = 32.64 s^{-1}

Step 4:

9.

λ = 5.89 * 10^{-7} m

v = 1.94 * 10^{8} m/s

f = v/λ = 3.29 * 10^{14} s^{-1}

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larisa [96]

Answer:

Part a)

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Part d)

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Part f)

y = -75.6 m

Explanation:

As we know that catapult is projected with speed 19.9 m/s

so here we have

v_x = 19.9 cos39.9

v_x = 15.3 m/s

similarly we have

v_y = 19.9 sin39.9

v_y = 12.76 m/s

Part a)

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x = v_x t

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Part b)

Vertical direction we have

y = v_y t - \frac{1]{2}gt^2

y = (12.76)(1.03) - 4.9(1.03)^2

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Part c)

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Part d)

Vertical direction we have

y = v_y t - \frac{1]{2}gt^2

y = (12.76)(1.71) - 4.9(1.71)^2

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Part e)

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x = 83.23 m

Part f)

Vertical direction we have

y = v_y t - \frac{1]{2}gt^2

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