Answer:
Rate of the reaction= 9.92× 10^-5 M² min-1
Explanation:
Using the equation of reaction
2N2O5 ⟶ 4NO2+O2
Rate = k[N2O5]²
From the question k= 6.2×10-4
[N2O5]= 0.4
Rate = 6.2×10-4[0.4]²= 9.92×10-5M² min-1
39.25 g of water (H₂O)
Explanation:
We have the following chemical reaction:
2 H₂ + O₂ → 2 H₂O
Now we calculate the number of moles of each reactant:
number of moles = mass / molar weight
number of moles of H₂ = 14.8 / 2 = 7.4 moles
number of moles of O₂ = 34.8 / 32 = 1.09 moles
We see from the chemical reaction that 2 moles of H₂ will react with 1 mole of O₂ so 7.4 moles of H₂ will react with 3.7 moles of O₂ but we only have 1.09 moles of O₂ available. The O₂ will be the limiting reactant. Knowing this we devise the following reasoning:
if 1 moles of O₂ produces 2 moles of H₂O
then 1.09 moles of O₂ produces X moles of H₂O
X = (1.09 × 2) / 1 = 2.18 moles of H₂O
mass = number of moles × molar weight
mass of H₂O = 2.18 × 18 = 39.25 g
Learn more about:
limiting reactant
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2.5X20=50g
50g should be the right answer
Mass=volumeXdenisty.
Answer:
76.875 cm3
<h2>
Explanation:</h2>
Since: Density = 
Then: Volume = 
The mass of the box = 246g
and the density = 3.2 g/cm3
Then: The volume = 
= 76.875 cm3
