Two sides of an isosceles triangle have lengths of 2 and 12 . What is the length of the third side
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Hi there! :)
Answer:
Given the information, we can write an equation in slope-intercept form
(y = mx + b) to graph the line:
Plug in the slope for 'm', the y-coordinate of the point given for 'y', and the
x-coordinate given for 'x':
-4 = -2/3(-7) + b
-4 = 14/3 + b
Solve for b:
-12/3 = 14/3 + b
-12/3 - 14/3 = b
-26/3 = b
Therefore, the equation of the line is y = -2/3x - 26/3 (Graphed below)
Some points on the line include:
(-7, -4)
(-4, -6)
(0, -26/3)
(2, -10)
(5, -12)
The first row represents the input. The second row represents the value that the function f assumes for each input above. The third row represents the value that the function g assumes for each input above.
To compute f(1), we look for 1 in the first row (third column) and we look for the correspondent value for f. In this case, we have f(1)=4
Similarly, we look for 3 in the first row (last column) and we look for the value of g. In this case, we have g(3)=3.
Now we can plug the values in the formula: