Answer:
6.25 grams is the mass of solute dissolved.
Explanation:
w/w % : The percentage mass or fraction of mass of the of solute present in total mass of the solution.

Mass of the solution = 50.0 g
Mass of the solvent = x
w/w % = 12.5%

x = 6.25 g
6.25 grams is the mass of solute dissolved.
Answer:
2.2 x 10²² molecules.
Explanation:
- Firstly, we need to calculate the no. of moles in (6.0 g) sodium phosphate:
<em>no. of moles = mass/molar mass </em>= (6.0 g)/(163.94 g/mol) = <em>0.0366 mol.</em>
- <em>It is known that every mole of a molecule contains Avogadro's number (6.022 x 10²³) of molecules.</em>
<em />
<u><em>using cross multiplication:</em></u>
1.0 mole of sodium phosphate contains → 6.022 x 10²³ molecules.
0.0366 mole of sodium phosphate contains → ??? molecules.
<em>∴ The no. of molecules in 6.0 g of sodium phosphate</em> = (6.022 x 10²³ molecules)(0.0366 mole)/(1.0 mole) = <em>2.2 x 10²² molecules.</em>
Answer : The number of molecules present in nitrogen gas are,
Explanation :
First we have to calculate the moles of nitrogen gas by using ideal gas equation.
where,
P = Pressure of
gas =
(1 atm = 760 mmHg)
V = Volume of
gas = 985 mL = 0.982 L (1 L = 1000 mL)
n = number of moles
= ?
R = Gas constant =
T = Temperature of
gas =
Now put all the given values in above equation, we get:

Now we have to calculate the number of molecules present in nitrogen gas.
As we know that 1 mole of substance contains
number of molecules.
As, 1 mole of
gas contains
number of molecules
So,
mole of
gas contains
number of molecules
Therefore, the number of molecules present in nitrogen gas are,
<span>c. Passing electric charge through the reactants Is the answer to you're question.
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