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Lilit [14]
3 years ago
5

A balloon filled with helium gas at 20°C occupies 4.91 L at 1.00 atm. The balloon is immersed in liquid nitrogen at -196°C, whil

e the pressure is raised to 5.20 atm. What is the volume of the balloon in the liquid nitrogen?
Physics
1 answer:
Marizza181 [45]3 years ago
7 0

Answer:

V = 0.248 L

Explanation:

To do this, use the following equation:

P1*V1/T1 = P2*V2/T2

This equation is used to find a relation between two differents conditions of a same gas, which is this case. From this equation we can solve for V2.

Solving for V2:

V2 = P1*V1*T2/T1*P2

Temperature must be at Kelvin, so, we have to sum the temperature 273 to convert it in K.

Replacing the data we have:

V2 = 1 * 4.91 * (-196+273) / 5.2 * (20+273)

V2 = 378.07 / 1523.6

V2 = 0.248 L

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A light bulb and a solenoid are connected in series to a battery. An irod rod is thrust rapidly into the solenoid and later rapi
Ivanshal [37]

Answer:

3) Dims in, Brightens out

Explanation:

The relationship between the inductance of a coil and the current is inverse.

As the rod is thrusted into the solenoid, the inductance increases, which in turn decreases the current and the bulb gets dimmer. This is also because some magnetic force is drawn away from the solenoid and the battery.

When the rod is removed, the inductance of the solenoid decreases, the current increases, and the bulb becomes brighter.

4 0
3 years ago
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Imagine you could travel to the moon where the acceleration due to gravity is 1.6 m/s^2. What would be the period of
VladimirAG [237]

Answer:

4.9612 s

Explanation:

Applying,

T = 2π√(L/g)............... Equation 1

Where T = period of the pendulum, L = Lenght of the pendulum, g = acceleration due to gravity of the moon, π = pie.

From the question,

Given: L = 1 m, g = 1.6 m/s²

Constant: π = 3.14

Substitute these values into equation 1

T = 2×3.14×√(1/1.6)

T = 6.28√(0.625)

T = 6.28×0.79

T = 4.9612 s

6 0
3 years ago
O ônibus espacial,preso sobre o avião está em movimento ou repouso?
marissa [1.9K]
Movimento es correcto
6 0
3 years ago
: In heavy rushIn heavy rush-hour traffic you drive in a straight line at 12 m/s for 1.5 minutes, then you have to stop for 3.5
zhuklara [117]
Guessing you want the average speed. We can multiple each speed by the time we spent going that speed, and them all together and then divide by the total time we spent in traffic to get the average speed. We spent a total of 7.5 minutes in traffic, so average speed  = (12*1.5+0*3.5+15*2.5)/7.5 = 7.4 m/s
8 0
3 years ago
Suppose the ring rotates once every 4.30 ss . If a rider's mass is 58.0 kgkg , with how much force does the ring push on her at
Stells [14]

Answer:

422.36 N

Explanation:

given,

time of rotation = 4.30 s

T = 4.30 s

Assuming the diameter of the ring equal to 16 m

radius, R = 8 m

v = \dfrac{2\pi R}{T}

v = \dfrac{2\pi\times 8}{4.30}

  v = 11.69 m/s

now, Force does the ring push on her at the top

- N - m g = \dfrac{-mv^2}{R}

N + m g = \dfrac{mv^2}{R}

N = \dfrac{mv^2}{R}- m g

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N = 58\times (\dfrac{11.69^2}{8}- 9.8)

N = 422.36 N

The force exerted by the ring to push her is equal to 422.36 N.

6 0
3 years ago
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