Answer:
The correct option is (b).
Explanation:
We need to find the work done to increase the speed of a 1 kg toy car by 5 m/s.
We know that, the work done is equal to the kinetic energy of an object i.e.
![W=\Delta K\\\\W=\dfrac{1}{2}mv^2\\\\W=\dfrac{1}{2}\times 1\times 5^2\\W=12.5\ J](https://tex.z-dn.net/?f=W%3D%5CDelta%20K%5C%5C%5C%5CW%3D%5Cdfrac%7B1%7D%7B2%7Dmv%5E2%5C%5C%5C%5CW%3D%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%201%5Ctimes%205%5E2%5C%5CW%3D12.5%5C%20J)
So, 12.5 J of work is done to increase the speed of a 1.0 kg toy car by 5.0 m/s.
The radial velocity method preferentially detects large planets close to the central star
- what is the Radial velocity:
The radial velocity technique is able to detect planets around low-mass stars, such as M-type (red dwarf) stars.
This is due to the fact that low mass stars are more affected by the gravitational tug of planets.
When a planet orbits around a star, the star wobbles a little.
From this, we can determine the mass of the planet and its distance from the star.
hence we can say that,
option D is correct.
The radial velocity method preferentially detects large planets close to the central star
Learn more about radial velocity here:
<u>brainly.com/question/13117597</u>
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Answer:
d= 794.4 cmExplanation:
Given that
Speed ,V= 286 km/h
![=286\times \dfrac{1000}{3600}\ m/s](https://tex.z-dn.net/?f=%3D286%5Ctimes%20%5Cdfrac%7B1000%7D%7B3600%7D%5C%20m%2Fs)
V=79.44 m/s
Given that time ,t= 100 ms
t= 0.1 s
We know that ( if acceleration is zero)
Distance = Speed x time
d= V t
Now by putting the values in the above equation
d = 79.44 x 0.1 m
d= 7.944 m
We know that 1 m = 100 cm
d= 794.4 cm
Answer: 0.067 s
Explanation:s = Ut + 1/2at^2
0.6 = 9t + 0.5 *10 *t^2
Where a = g =10m/s/s
Solving the quadratic equation
5t^2 + 9t - 0.6=0,
t= 0.067 s and - 1.7 s
Of which 0.067 s is a valid time
Answer:
95 minutes
Explanation:
The Hubble Space Telescope makes one orbit around Earth every 95 minutes. The electromagnetic spectrum shows that visible light is between infrared radiation and ultraviolet radiation. NASA.gov