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Ludmilka [50]
3 years ago
12

The mass of an atom is ________________________.

Physics
1 answer:
alexandr402 [8]3 years ago
7 0
The mass of an atom comes from the protons and neutrons that is found in the nucleus. The number of protons is the atomic number of an element. To find the number of neutrons, subtract the atomic number from the mass of an atom. For example, sodium’s atomic number is 11. This will tell us that sodium has 11 protons in it. The atomic mass of sodium is 23. So subtract 23 form 11 gives us 12. Therefore, there are 12 neutrons in sodium.
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30 POINTS!!! CAN U AWNSER IT?? :)
solniwko [45]

Answer:

5235.84 kg

Explanation:

There is one theorem - whose proof I will never remember without having to drag calculus in there - that says that the variation of momentum is equal to the force applied times the time the application last.

F\Delta t = m \Delta v As long as the engine isn't ejecting mass - at this point it's a whole new can of worm - we know the force, we know the variation in speed, time to find the mass. But first, let's convert the variation of speed in meters per second. The ship gains 250 kmh, \Delta v = 69.4 m/s;

45 450 \cdot 8 = 69.4 m \rightarrow m = \frac{45450\cdot 8}{69.4} = 5235.84 kg

7 0
2 years ago
What is the mass of an object that has a weight of 2867 N?
Gnom [1K]

Answer:

F = M a

W = M g     equivalent equation to express weight of object of mass M

M = W / g = 2867 N / 9.8 m/s^2 = 292.6 kg

7 0
2 years ago
Jill applies a force of 15 N to a wrench. If
Ivenika [448]
Jill is the input, as she creates the force. The wrench is the output because it gives the force to the finish peace of the chain.
6 0
3 years ago
2. A projectile is launched at a speed of 35 m/s and an angle of 40 above the horizontal.
IrinaVladis [17]

Answer:

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6 0
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Read 2 more answers
At noon on a clear day, sunlight reaches the earth\'s surface at Madison, Wisconsin, with an average intensity of approximately
Dmitrij [34]

Intensity of sunlight at given position is defined as power received per unit area

so here we can say

I = 2 kJ/s*m^2

area  on which photons are received is given as

A = 4.80 cm^2 = 4.80 * 10^-4 m^2

now we can find the power received due to sunlight

P = I*A

P = 2* 10^3 * 4.80 * 10^-4

P = 0.96 Watt

now we can say this power is due to photons that strikes on surface of earth

so here we can say

P = N\frac{hc}{\lambda}

given here that

\lambda = 510 nm

0.96 = N\frac{6.6 * 10^{-34}* 3 * 10^8}{510*10^{-9}}

0.96 = N * 3.88 * 10^{-19}

N = \frac{0.96}{3.88*10^{-19}}

N = 2.47 * 10^{18}

so it will strike 2.47 * 10^18 photons on given area per second

3 0
3 years ago
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