Answer:
The velocity of the plane at take off is 160 m/s.
The distance travel by the plane in that time is 3200 meter.
Explanation:
Given:
Acceleration, a = 4 m/s²
Time, t = 40 s
u = 0 i .e initial velocity
To Find:
velocity , v = ?
distance , s =?
Solution:
we have first Kinematic equation
v = u + at
∴ v = 0 + 4×40
∴ v = 160 m/s
Now by Third Kinematic equation
∴ s = 0 + 0.5 × 4× 40²
∴ s = 3200 meter
To solve this exercise it is necessary to take into account the concepts related to Pressure depending on the Force and the Area.
The pressure is defined as
Where,
Our values are given as,
Where is the mass of the person and
is mass of cycle. Therefore the total mass at the system is 105Kg.
For Newton's second law we have:
where a is the acceleration, in this case the same Gravitational acceleration.
We need to make two considerations, the first is to calculate the total weight and second to calculate the weight on each wheel (2), that is
Force in each wheel,
In this way we can now calculate the length based on the pressure, that is
Therefore each tire has 3.21cm