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sergey [27]
2 years ago
8

PLS HELP MEEE 7y − 5 = 51 y =

Mathematics
1 answer:
Xelga [282]2 years ago
7 0
Y= -5/44 Im sure this should be your answer I am sorry if it’s not
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PLEASE HELP ASAP, I WILL GIVE BRAINLESSLY ANSWER <br> SHOW WORK PLEASE
zhannawk [14.2K]

Answer:

C. N(t)=150\cdot 3^t

Step-by-step explanation:

You are given the exponential function n(t)=ab^t.

From the table, N(t)=150 at t=0, thus

N(0)=a\cdot b^0\\ \\150=a\cdot 1\ [\text{ because }b^0=1]

Also N(t)=450 at t=1, thus

N(1)=a\cdot b^1=a\cdot b.

Since  a=150, substitute it into the second equation

450=150\cdot b\\ \\b=\dfrac{450}{150}\\ \\b=3

and the expression for the exponential function is

N(t)=150\cdot 3^t

5 0
3 years ago
8,36 : 1,6<br><br><br><br> pleaseeeeeeeeee
Lyrx [107]

Answer:

  209 : 40  or  5.225 : 1

Step-by-step explanation:

Your calculator can tell you the ratio 8.36/1.60 is 5.225. Writing that decimal as a fraction, you can factor out 25 to get ...

  8.36 : 1.6 = 5.225 : 1 = 5225 : 1000 = (25)(209) : (25)(40) = 209 : 40

4 0
3 years ago
A. 1/3=0.33<br>B. 1/6=0.17<br>C. 1/10=0.10<br>D. 1/4=0.25​
statuscvo [17]
B

lmk if this helped
4 0
3 years ago
Will is twice as old as Jill. Three years ago, Jill's age was two fifths of Will's age then. How old is each now?
dimulka [17.4K]
"Will is twice as old as Jill."

                       Jill's age . . . . .   J
                       Will's age . . . . 2J .

"Three years ago . . .

                       Jill's age then . . . . .   J - 3
                       Will's age then . . . . 2J - 3

". . . Jill's age then was 2/5 of Will's age then."

                                         J - 3  =  (2/5) (2J - 3)
Multiply
each side by  5 :          5J - 15  =  2 (2J - 3)

Divide
each side by  2 :          2.5 J - 7.5  =  2J - 3 

Subtract  2J
from each side:            0.5 J - 7.5  =      -3

Add  7.5
to each side:                0.5 J           =     4.5

Multiply
each side by  2 :                J            =       9

Jill is  9  y.o. now.
Will is 18 y.o. now.

4 0
3 years ago
What is the standard error of the sampling distribution of sample proportion?.
storchak [24]

Answer:

√ (p(1-p) / n)

Step-by-step explanation:

Standard Error(SE) of the Sample Proportion: √ (p(1-p) / n). Note: as the sample size increases, the standard error decreases.

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Hope this helps you! Feel free to give feedback

5 0
2 years ago
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