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2 years ago

HELPPP PLS THIS IS DUE TOMARRROW

Mathematics

2 answers:

Mekhanik [1.2K]2 years ago

8 0

Answer:

(-10)+3 1/2 = -6 1/2

Step-by-step explanation:

It first points to the left. Which means subtracting. It shows that it starts at zero so, keep that in mind. Then it points to the right which means your adding 3 1/2. So you would start at zero and subtract 10. (-10). Then you would add 3 1/2. +3 1/2

(-10) + 3 1/2

To then make -6 1/2

kupik [55]2 years ago

6 0

Answer:

It is second bubble

for explanation

○One

○Two

○Three

○Four

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An irregular polygon is shown below:

lord [1]

24 units or you can put 7x4 units

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1 year ago

How many quarts of pure antifreeze must be added to 5 quarts of a 40% antifreeze solution to obtain a 50% antifreeze solution

GarryVolchara [31]

Answer:

2 quarts of 100% antifreeze.

Step-by-step explanation:

5 quarts/ .40 * x/ 1

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6 0

2 years ago

Simi bought a study table for $ 9000. She sold it at a profit of 20%. How much profit did she make? What is the selling price?

pashok25 [27]

Answer:

cost price of a table=$9000

profit%=20%

Let profit be x

to find profit use formula,

profit%=profit/cost price*100

20%=x/$9000*100

20*$9000=100x

$180000/100=x

$1800=x

Now to find selling prie os a table use formula,

cost price +profit

$9000+$1800

$91800

therefore selling price of a table is $91800

Step-by-step explanation:

Hope this helps u!!

4 0

2 years ago

Ments

maw [93]

The sector area and the arc length are 34.92 square inches and 13.97 inches, respectively

<h3>How to find a sector area, and arc length?</h3>

For a sector that has a central angle of θ, and a radius of r;

The sector area, and the arc length are:

$A = \frac{\theta}{360} * \pi r^2$ --- sector area

$L = \frac{\theta}{360} * 2\pi r$ ---- arc length

<h3>How to find the given sector area, and arc length?</h3>

Here, the given parameters are:

Central angle, θ = 160

Radius, r = 5 inches

The sector area is

$A = \frac{\theta}{360} * \pi r^2$

So, we have:

$A = \frac{160}{360} * \frac{22}{7} * 5^2$

Evaluate

A = 34.92

The arc length is:

$L = \frac{\theta}{360} * 2\pi r$

So, we have:

$L = \frac{160}{360} * 2 * \frac{22}{7} * 5$

L = 13.97

Hence, the sector area and the arc length are 34.92 square inches and 13.97 inches, respectively

Read more about sector area and arc length at:

brainly.com/question/2005046

#SPJ1

8 0

1 year ago

100 POINTS

weeeeeb [17]

The blanks are as follows:

Angle addition postulate
Subtraction property of equality
Corresponding sides of similar triangles are proportional
Multiplication property of equality

8 0

2 years ago