For the answer to the question above,
in this problem we can use the concept of freezing point depression since we are given the freezing point of the solution.
ΔT = -k(f) x m x i
-2.24 - 0 = -1.86 x m x 3
<span>m = 0.4014
</span>So the answer to your question is m = 0.4014
Answer:
Valence electrons are involved in Reaction B but not in Reaction A.
Explanation:
The description of reaction A in which protons are lost or gained by the atom of the element is a nuclear reaction. In nuclear reactions, the nucleons which are the protons and neutrons drives the reaction. No valence electrons in the orbiting shells are involved in this kind of reaction. During this type of reaction, an atom changes it identity to that of another.
Reaction B in which no identity change occurs is a chemical reaction. In chemical reactions bonds are formed by the atoms using the valence electrons that orbits round the central nucleus. The atoms remain the same but it chose to attain stability and an inert configuration by losing or gaining electrons.
The answer is 4. It can hold 4 sublevels as s.p,d,f and it holds 32 electrons
I’m almost positive the answer would be B. Electron promotion is when an electron “jumps” from a low energy level to a higher energy level.
Hope this helps!! (:
I believe it is H--CH3, as the difference in electronegativity is larger