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Makovka662 [10]
3 years ago
15

The charge on a magnesium ion is +2. When it formed an ionic compound with another element, it lost 2... what?

Chemistry
1 answer:
Naya [18.7K]3 years ago
6 0

Answer:  electrons

Explanation:  Electrons have a charge of -1 each.  If two left, the remaining atom would have a positive +2 change.

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[Ag⁺] = 5.0x10⁻¹⁴M

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The product solubility constant, Ksp, of the insoluble salts PbI₂ and AgI is defined as follows:

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The PbI₂ <em>just begin to precipitate when the product  [Pb²⁺] [I⁻]² = 1.4x10⁻⁸</em>

<em />

As the initial [Pb²⁺] = 0.0050M:

[Pb²⁺] [I⁻]² = 1.4x10⁻⁸

[0.0050] [I⁻]² = 1.4x10⁻⁸

[I⁻]² = 1.4x10⁻⁸ / 0.0050

[I⁻]² = 2.8x10⁻⁶

<h3>[I⁻] = 1.67x10⁻³</h3><h3 />

So, as the [I⁻] concentration is also in the expression of Ksp of AgI and you know concentration in solution of I⁻ = 1.67x10⁻³M:

[Ag⁺] [I⁻] = 8.3x10⁻¹⁷

[Ag⁺] [1.67x10⁻³] = 8.3x10⁻¹⁷

<h3>[Ag⁺] = 5.0x10⁻¹⁴M</h3>

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