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2 years ago

The charge on a magnesium ion is +2. When it formed an ionic compound with another element, it lost 2... what?

Chemistry

1 answer:

Naya [18.7K]2 years ago

6 0

Answer: electrons

Explanation: Electrons have a charge of -1 each. If two left, the remaining atom would have a positive +2 change.

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(Timed) What part of an atom involved in a chemical reaction?

tino4ka555 [31]

D.electron
The part of the atom involved in a chemical reaction is the electron cloud. The electron cloud is the part of the atom surrounding the nucleus.

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3 years ago

Which source of energy causes most of the water evaporation on Earth’s surface?

coldgirl [10]

Which adds the most energy to the earth? Solar. So Solar will cause the most evaporation (B)

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3 years ago

Read 2 more answers

What's the formula equation for the reaction that occurred between the barium chloride solution , BaCl2 (aq), and the sodium sul

Solnce55 [7]

The balanced equation is:

BaCl2 (aq) + Na2SO4 (aq) ----> BaSO4(s)+ 2 NaCl(aq)

This is a double replacement reaction.

The reactants are:

a) BaCl2: barium chloride, a ionic compound, therefore soluble in water,

b) Na2SO4: sodium sulfate, another ionic compound, therefore also soluble in water.

The products are:

c) BaSO4: barium sulfate, a solid not soluble in water which precipitates.

d) NaCl: sodium chloride, an ionic compound, therefore soluble in water.

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3 years ago

What is released in the process of an atom moving from an excited level to a lower energy level?

luda_lava [24]

The correct answer is a Photon.

One photon is released for each event. Photons are elementary particles of all electromagnetic radiation, including light.

7 0

3 years ago

For the reaction

s2008m [1.1K]

Answer:

0.558mole of SO₃

Explanation:

Given parameters:

Molar mass of SO₃ = 80.0632g/mol

Mass of S = 17.9g

Molar mass of S = 32.065g/mol

Number of moles of O₂ = 0.157mole

Molar mass of O₂ = 31.9988g/mol

Unknown:

Maximum amount of SO₃

Solution

We need to write the proper reaction equation.

2S + 3O₂ → 2SO₃

We should bear in mind that the extent of this reaction relies on the reactant that is in short supply i.e limiting reagent. Here the limiting reagent is the Sulfur, S. The oxygen gas would be in excess since it is readily availbale.

So we simply compare the molar relationship between sulfur and product formed to solve the problem:

First, find the number of moles of Sulfur, S:

Number of moles of S = $\frac{mass }{molar mass}$

Number of moles of S = $\frac{17.9 }{32.065}$ = 0.558mole

Now to find the maximum amount of SO₃ formed, compare the moles of reactant to the product:

2 mole of Sulfur produced 2 mole of SO₃

Therefore; 0.558mole of sulfur will produce 0.558mole of SO₃

5 0

3 years ago