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creativ13 [48]
2 years ago
5

What are the most of the elements in the periodic table

Chemistry
2 answers:
vaieri [72.5K]2 years ago
5 0

Answer:

Most of the elements in the periodic table are <u><em>metals</em></u>.

Hope that helps. x

Alika [10]2 years ago
4 0

Answer:

<em><u>Here</u></em><em><u> is</u></em><em><u> </u></em><em><u>your</u></em><em><u> </u></em><em><u>answer</u></em><em><u>,</u></em><em><u>mate</u></em><em><u>!</u></em>

Explanation:

<em><u>Metals</u></em><em><u> </u></em><em><u>are</u></em><em><u> the</u></em><em><u> </u></em><em><u>most</u></em><em><u> of</u></em><em><u> the</u></em><em><u> </u></em><em><u>elements</u></em><em><u> in</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>periodic</u></em><em><u> table</u></em><em><u>.</u></em>

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How many liters of oxygen gas, at standard
Karo-lina-s [1.5K]

Answer:

Explanation:

  • For the balanced reaction:

<em>4Fe(s) + 3O₂(g) → 2Fe₂O₃(s)​.</em>

It is clear that 4 mol of Fe react with 3 mol of O₂ to produce 2 mol of Fe₂O₃.

  • Firstly, we need to calculate the no. of moles of 35.8 grams of Fe metal:

no. of moles of Fe = mass/molar mass = (35.8 g)/(55.845 g/mol) = 0.64 mol.

  • Now, we can find the no. of moles of O₂ is needed to react with the proposed amount of Fe:

<em><u>Using cross multiplication:</u></em>

4 mol of Fe is needed to react with → 3 mol of O₂, from stichiometry.

0.64 mol of Fe is needed to react with → ??? mol of O₂.

∴ The no. of moles of O₂ needed = (3 mol)(0.64 mol)/(4 mol) = 0.48 mol.

  • Finally, we can get the volume of oxygen using the information:

<em>It is known that 1 mole of any gas occupies 22.4 L at standard P and T (STP).</em>

<em></em>

<em><u>Using cross multiplication:</u></em>

1 mol of O₂ occupies → 22.4 L, at STP conditions.

0.48 mol of O₂ occupies → ??? L.

∴ The no. of liters of O₂ = (0.48 mol)(22.4 L)/(1 mol) = 10.752 L.

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Write the definition of a compound and give two examples
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