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UNO [17]
3 years ago
10

Odyssey Quiz

Physics
1 answer:
Novosadov [1.4K]3 years ago
4 0

Answer:

OD) 3.7 kg-m/s

Explanation:

given:

velocity of baseball, v = 25 m/s

angle below horizontal, Θ = 8^{o}

mass of baseball, m = 0.15 kg

Generally, momentum (p) is given by equation:

p = mv

Horizontal component is given by

p = mv cosΘ

  = 0.15 kg x 25 m/s x cos 8^{o}

  = 3.71 kg- m/s

Hence horizontal component of momentum is OD) 3.7 kg-m/s

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Answer: Dalton’s model

Explanation:

In the attached image we can see four atomic models labeled with four letters:

W represents the current and accepeted atomic model: a nucleus with an electron cloud, where the orbit and position of the electrons around the nucleus is defined by specific regions (associated with specific energy levels) where there is a greater probability of finding the electron at any given moment. It is important to note this model was improved by the works in quantum physics done by Louis de Broglie and Erwin Schrodinger.

X represents Rutherford's model (This model was proposed after Thomson's model). Ernest Rutherford conducted a series of experiments in order to corroborate Thomson's atomic model. However the results of the experiment led him to find out there is a concentration of charge in the atom's core (which was later called nucleus) surrounded by electrons.  This lead to a new atomic model, in which the atom has a positive charged nucleus surrounded by negative charged particles that move similar to the orbit of the planet around the Sun.

Y represents Thomson's model, also called  the <em>plum pudding</em> model. This scientific found out that atoms contain small subatomic particles with a negative charge (later called electrons). However, taking into consideration that at that time there was still no evidence of the atom nucleus, Thomson thought the electrons were immersed in the atom of positive charge that counteracted the negative charge of the electrons. Just like the raisins embedded in a pudding or bread.

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4 0
3 years ago
Read 2 more answers
A motorcyclist who is moving along an x axis directed toward the east has an acceleration given by a = (6.30 - 2.20t) m/s2 for 0
musickatia [10]
<span>(a) 12.02 m/s
 (b) 52.2 meters

   This problem is an example of integral calculus. You've been given an acceleration vector which is usually known as the 2nd derivative. From that you need to calculate the velocity function (1st derivative) and position (actual function) by successively calculating the anti-derivative. So:
   A(t) = 6.30 - 2.20t
 V(t) = 6.30t - 1.10t^2 + C

   We now have a velocity function, but need to determine C. Since we've been given the velocity at t = 0, that's fairly trivial.
 V(t) = 6.30t - 1.10t^2 + C
 3 = 6.30*0 - 1.10*0^2 + C
 3 = 0 + 0 + C
 3 = C

    So the entire velocity function is:
 V(t) = 6.30t - 1.10t^2 + 3
 V(t) = -1.10t^2 + 6.30t + 3

   Now for the location function which is the anti-derivative of the velocity function.
  V(t) = -1.10t^2 + 6.30t + 3
  L(t) = -0.366666667t^3 + 3.15t^2 + 3t + C

   Now we need to calculate C. And once again, we've been given the location for t = 0, so
 L(t) = -0.366666667t^3 + 3.15t^2 + 3t + C
 7.3 = -0.366666667*0^3 + 3.15*0^2 + 3*0 + C
 7.3 = 0 + 0 + 0 + C
 7.3 = C

   L(t) = -0.366666667t^3 + 3.15t^2 + 3t + 7.3

   Now that we have the functions, they are:
 A(t) = 6.30 - 2.20t
 V(t) = -1.10t^2 + 6.30t + 3
 L(t) = -0.366666667t^3 + 3.15t^2 + 3t + 7.3

    let's answer the questions.
 (a) What is the maximum speed achieved by the cyclist?
 This can only happen at those points that meet either of the following criteria.
  1. The derivative is undefined for the point.
  2. The value of the derivative is 0 for the point.
 As it turns out, the 1st derivative of the velocity function is the acceleration function which we have. So
 A(t) = 6.30 - 2.20t
 0 = 6.30 - 2.20t
  2.20t = 6.30
 t = 2.863636364

   So one of V(0), V(2.863636364), or V(6) will be the maximum value. Therefore: V(0) = 3
 V(2.863636364) = 12.0204545454545
 V(6) = 1.2

   So the maximum speed achieved is 12.02 m/s

   (b) Total distance traveled?
 L(0) = 7.3
 L(6) = 59.5
 Distance traveled = 59.5 m - 7.3 m = 52.2 meters</span>
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Earth's land and ocean surface to the atmosphere.
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