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Alisiya [41]
2 years ago
15

What are the correct two steps, in the correct order, that would allow you to solve for x in the following equation?

Chemistry
1 answer:
Pani-rosa [81]2 years ago
5 0

Answer:

4th one is correct...............

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Convert 485 milligrams into grams
Zielflug [23.3K]

Answer:

look at the picture above

5 0
2 years ago
Read 2 more answers
How many standard amino acids are there in the human body?
Whitepunk [10]

Answer:

-Theres 20 amino acids in the human body

-The least number of amino acids in a polypeptide are 10

Explanation:

5 0
2 years ago
5. Determine the number of liters in 4.32 grams of water (H2O). Answer: --_ 5.37L H2O__​
MariettaO [177]

Answer:

4.32 \frac{1}{18.01} ×\frac{22.4}{1} = 5.37

Explanation:

22.4 is how many liters per mole. 18.01 is the mass of H2O.

8 0
2 years ago
What substance would you add to KF(aq) to form a buffer solution? View Available Hint(s) What substance would you add to to form
AnnyKZ [126]
<h3>Answer</h3>

HF

<h3>Explanation</h3>

A buffer solution contains <em>a weak acid</em> and<em> its conjugate base</em>. The two species shall have a similar concentration in the solution. It's also possible for <em>a weak base</em> and <em>its conjugate acid</em> to form a buffer solution.

The KF solution already contains large number of \text{F}^{-} ions. The objective is to thus find its conjugate acid or base.

\text{F}^{-} contains no proton \text{H}^{+} and is unlikely to be a conjugate acid. Assuming that \text{F}^{-} is a conjugate base. Adding one proton to \text{F}^{-} would produce its conjugate acid.

\text{H}^{+} \; (aq) + \text{F}^{-} \; (aq) \rightleftharpoons \text{HF}\; (aq)

Therefore \text{HF} is the conjugate acid of \text{F}^{-}. \text{HF} happens to be a weak acid. As a result, combining \text{F}^{-} with \text{HF} would produce a solution with large number of both the weak acid and its conjugate base, which is a buffer solution by definition.

4 0
3 years ago
How many moles of ammonium ions are in 1.3 grams of ammonium carbonate?
Eva8 [605]
Molecular weight of (NH4)2 CO3 = 96 gm. 96 gm (NH4)2CO3 = 1 mol of (NH4)2CO3 = 2 moles of NH4. Therefore 1.3 gm of (NH4)2CO3 = 1.3x2/ 96 = 0.027 moles.
3 0
3 years ago
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