Mole=mass/molecular mass (Mr)
mole=volume/ 22.4
Molecular amount: Mole=amount atoms/ Avogadro's number
Concentration: mole=volume x M
For that you have to use the Aufbau principle
For example, writing the electronic configuration of Fe(28)
I recommend that you memorize the aufbau principle. Once you learn it, you don’t need anything else except the atomic number of the element to write it’s electronic configuration.
Answer:
B or C
Explanation:
I don't really know sorry.
Answer:
a) CaF₂.
b) 7.81g of CaF₂ are present.
Explanation:
a) The calcium ion has as charge Ca²⁺ and fluoride ion is F⁻, that means formula unit is:
CaF₂
b) 1 molecule of CaF₂ contains 2 anions, F⁻. Thus, the moles of CaF₂ is:
1.2x10²³ anions * (1 moleculeCaF₂ / 2 anions) = 6x10²² molecules of CaF₂
6.022x10²³ molecules = 1mol:
6x10²² molecules of CaF₂ * (1mol / 6.022x10²³molecules) = 0.10 moles CaF₂.
1 mole of CaF₂ has a mass of 78.07g:
0.10 moles CaF₂ * (78.07g / mol) =
7.81g of CaF₂ are present
Answer:
Percentage yield is 41.21%
Explanation:
Equation of reaction,
N₂ + 3H₂ → 2NH₃
Actual NH3 = 6.83g
Mass of N2 = 5.77g
Theoretical yield = ?
5.77g of N2 = 6.83g of NH3
14g of N2 = xg
X = (14 × 6.83) / 5.77
X = 95.62 / 5.77
X = 16.57g of NH3
Theoretical yield of NH3 is 16.57g
Percentage yield = (actual yield / theoretical yield) × 100
% yield = (6.83 / 16.57) × 100
% yield = 0.4121 × 100
% yield = 41.21%
The percentage yield of NH3 is 41.21%