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Ne4ueva [31]
3 years ago
10

1. What is the International System of Units and its abbreviation?

Chemistry
1 answer:
GenaCL600 [577]3 years ago
7 0

Answer:

SI

modern form of the metric system

Explanation:

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Is mixing butter, granulated sugar, and brown sugar until it's creamy a physical or chemical change and why
Nadusha1986 [10]

Answer:

Physical

Explanation: Because it says "Until creamy" meaning you're changing the look, not the way it reacts with each other.

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When calculating percent error, the accepted value is in the denominator <br> True or false
kaheart [24]

Answer:

True

Explanation:

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When Wolverine’s 10-pound adamantium claws are dissolved in 100 mL of 10 M nitric acid, 10.7 grams of adamantium nitrate are rec
Mazyrski [523]

The percent yield is 71.3 %.

Explanation:

Percent yield is the measure to analyze the success percentage of any experiment .The percent yield of any experiment can be obtained by the ratio of actual or experimental value to expected or theoretical value multiplied with 100.

Percent Yield = \frac{Experimental Outcome}{Theoretical Outcome} *100

So, in the present problem, we have obtained 10.7 g of adamantium nitrate from Wolverine's 10 pound claws. So the actual value or the experimental value is the amount of adamantium nitrate obtained from Wolverine's claws.

Thus, the experimental outcome is 10.7 g. While we had expected to recover 15 g of adamantium nitrate. So the theoretical outcome is 15 g.

Percent yield = \frac{10.7}{15} * 100 = 71.3 %

Thus, the percent yield is 71.3 %.

7 0
3 years ago
Czemu mosiądz czerwony jest bardziej miekki niż żółty​
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3 years ago
Liquid sodium is being considered as an engine coolant. How many grams of liquid sodium (minimum) are needed to absorb 1.30 MJ o
Sunny_sXe [5.5K]

Answer:

97 000 g Na

Explanation:

The absortion (or liberation) of energy in form of heat is expressed by:

q=m*Cp*ΔT

The information we have:

q=1.30MJ= 1.30*10^6 J

ΔT = 10.0°C = 10.0 K (ΔT is the same in °C than in K)

Cp=30.8 J/(K mol Na)

If you notice, the Cp in the question is in relation with mol of Na. Before using the q equation, we can find the Cp in relation to the grams of Na.

To do so, we use the molar mass of Na= 22.99g/mol

Cp= \frac{30.8J}{K*mol Na}*\frac{1 mol Na}{22.99 g Na}=1.34\frac{J}{K*g Na}

Now, we are able to solve for m:

m=\frac{1.30*10^6 J}{1.34\frac{J}{K*g Na} *10.0K}=\frac{1.30*10^6J}{13.4\frac{J}{g Na} }  = 9.70*10^4 g Na=97 Kg Na=97 000 g Na

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3 years ago
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