Why can't you walk on water?

2 answers:

8 0

Technically speaking, walking over pure water isn't possible. The only way it can be done is by converting it to a high density fluid or one with high viscosity. Also, if you think you can run at 108 km/hr (30 m/s), then you'll have the ability to run across water.

fiasKO [112]3 years ago

8 0

This happens because of surface tension. Water molecules are attracted to each other. They form weak bonds between each other. Where these molecules meet air, the exposed water molecules can't attach to any more molecules in front of them — there's air there.

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Please help!! i need the answer ASAP!

nirvana33 [79]

Answer:

23.34 %.

Explanation:

The percentage of water must be calculated as a mass percent.

We need to find the mass of water, and the total mass in one mole of the compound. For that we need to use the atomic masses of each element and take in consideration the number of atoms of each element in the formula unit.

Atomic masses of the elements:

Cd: 112.411 g/mol, N: 14.0067 g/mol, O: 15.999 g/mol, and H: 1.008 g/mol.

Mass of the formula unit:

Cd(NO₃)₂•4H₂O

mass of the formula unit = (At. mass of Cd) + 2(At. mass of N) + 10(At. mass of O) + 8(At. mass of H) = (112.411 g/mol) + 2(14.0067 g/mol) + 10(15.999 g/mol) + 8(1.008 g/mol) = 308.5 g/mol.

Mass of water in the formula unit:

mass of water = (4 × 2 × 1.008 g/mol) + (4 × 15.999 g/mol) = 72.0 g/mol.

So, the percent of water in the compound = [mass of water / mass of the formula unit] × 100 = [(72.0 g/mol)/(308.5 g/mol)] × 100 = 23.34 %

7 0

2 years ago

Help!! < PHYSICAL SCIENCE>

Vlad1618 [11]

The answer is B or the second answer

3 0

3 years ago

What would the product look like if ROOR weren't used?

S_A_V [24]

Answer:

The least substituted product (anti-Markovnikov)

Explanation:

The ROOR is used in the addition reaction of HBr to an organic substance (an alkene for example).

In normal conditions (with no ROOR) the adition of the halogen will be performed in the most substituted C (following the rule of Markovnikov that says that the stability increases with the more substituted is the C).

But in presence of ROOR, the reaction takes other mechanism (free radicals), and the product in this case is the one with the Br added in the least substituted C.