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3 years ago

CH³C⁴HCOCH³ how many atoms of each element are in one molecule of 2-heptanone

Chemistry

1 answer:

dalvyx [7]3 years ago

5 0

Answer:

- 7 carbon atoms.

- 14 hydrogen atoms.

- 1 oxygen atom.

Explanation:

Hello,

In this case, for the given compound, heptanone, whose chemical formula is:

$CH_3COCH_2CH_2CH_2CH_2CH_3$

We can write the molecular formula showing the present atoms of each element:

$C_7H_{14}O$

In such a way we have:

- 7 carbon atoms.

- 14 hydrogen atoms.

- 1 oxygen atom.

Best regards.

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The answer is <span>The mass of sodium chloride formed is less than 76 grams.
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Remember Mass is never gained or loss in any chemical reactions

So,

hydrochloric acid + sodium hydroxide => <span>sodium chloride + water
Total 76 gram Total will also 76 gram

In this case, the mass of sodium chloride will be less than 76 gram because we need to take out the mass of the water.

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Muszę napisać wzór sumatryczny wysyłam załącznik

ioda

Cześć, nie mówię po polsku, więc zrobiłem to w Tłumaczu Google, więc przepraszam, jeśli coś brzmi śmiesznie.

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-Cutiepatutie

7 0

3 years ago

4. DBearded waste of Co-60 must be stored until it is no longer radioactive. Cobalt-60

Bingel [31]

464 g radioisotope was present when the sample was put in storage

<h3>Further explanation</h3>

Given

Sample waste of Co-60 = 14.5 g

26.5 years in storage

Required

Initial sample

Solution

General formulas used in decay:

$\large{\boxed{\bold{N_t=N_0(\dfrac{1}{2})^{t/t\frac{1}{2} }}}$

t = duration of decay

t 1/2 = half-life

N₀ = the number of initial radioactive atoms

Nt = the number of radioactive atoms left after decaying during T time

Half-life of Co-60 = 5.3 years

Input the value :

$\tt 14.5=No.\dfrac{1}{2}^{26.5/5.3}\\\\14.5=No.\dfrac{1}{2}^5\\\\No=\boxed{\bold{464~g}}$

8 0

3 years ago