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Sholpan [36]
3 years ago
12

Which statement best describes the energy of activation?

Physics
1 answer:
Varvara68 [4.7K]3 years ago
4 0

hi <3

i believe the answer would be D, as when the temperature increases the particles have more energy and can overcome the activation energy more rapidly.

hope this helps :)

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Distance in scientific notation
n200080 [17]

Answer:

(See explanation for further information)

Explanation:

a) The distances of each planet with respect to the Sun is:

Mercury - 57.909 \times 10^{6}\,mi

Venus - 67.240\times 10^{6}\,mi

Earth - 92.960\times 10^{6}\,mi

Mars - 141.600\times 10^{6}\,mi

Jupiter - 483.800\times 10^{6}\,mi

Saturn - 888.200\times 10^{6}\,mi

Uranus - 1,787\times 10^{6}\,mi

Neptune - 2,795\times 10^{6}\,mi

b) The solutions are presented below:

A. The distance between Venus and Jupiter is:

\Delta s = 483.800\times 10^{6}\,mi-67.240\times 10^{6}\,mi

\Delta s = 416.560\times 10^{6}\,mi

B. The combined distance from the Sun is:

\Delta s = 57.909\times 10^{6}\,mi + 67.240\times 10^{6}\,mi +92.960\times 10^{6}\,mi

\Delta s = 218.109\times 10^{6}\,mi

Which is less than the distance from the Sun to Neptune (2,795\times 10^{6}\,mi).

C. The new distance of Earth is 929.60 \times 10^{6}\,mi (929,600,000\,mi). Saturn would be the closest planet to Earth, whose distance:

Scientific notation:

\Delta s = 929.600\times 10^{6}\,mi-888.200\,\times 10^{6}\,mi

\Delta s = 41.4\times 10^{6}\,mi

Standard notation:

\Delta s = 929,600,000\,mi - 888,200,000\,mi

\Delta s = 41,400.000\,mi

3 0
4 years ago
A 1.8 kg book has been dropped from the top of the football stadium. Its speed is 4.8 m/s when it is 2.9 meters above the ground
Alexus [3.1K]

Answer:

Answer:

72.936 Joule

Explanation:

Mechanical Energy = Potential Energy + Kinetic Energy

Kinetic Energy = (1/2) x m x V² = (1/2) x 1.8 x 4.8² = 20.736 J

Potential Energy = m x g x h = 1.8 x 10 x 2.9 = 52.2 J

Total Mechanical Energy = 20.736 + 52.2 = 72.936 Joule

Explanation:

8 0
3 years ago
Answer the question with step.​
Maru [420]

Answer:

f1/f2 =W1/W2 = 1/3

.0 f2 = 3f1

As ,

1/F= 1/f1 +1/f2

...1/40 = 1/f1 - 1/3f1

f1=> 80/3 cm

... f2 = 2f1 = 3 x 80/3 = 80 cm

7 0
3 years ago
suppose you have a block resting on a horizontal smooth surface. th block with a mass m is attached to a horizontal spring which
Mrrafil [7]
Easy 400 m 600 m 700 m
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Write your own examples of big and small forces on big and small things for
Nady [450]

Answer:

you know what I think you should not give these kind of q

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3 years ago
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