Answer:
(A) 9.5 m/s
(B) 5.225 m
Explanation:
vertical height (h) = 4.7 m
horizontal distance (d) = 9.3 m
acceleration due to gravity (g) = 9.8 m/s^{2}
initial speed of the fish (u) = 0 m/s
(A) what is the pelicans initial speed ?
- lets first calculate the time it took the fish to fall
s = ut + 
since u = 0
s = 
t =
where a = acceleration due to gravity and s = vertical height
t =
= 0.98 s
- pelicans initial speed = speed of the fish
speed of the fish = distance / time = 9.3 / 0.98 = 9.5 m/s
initial speed of the pelican = 9.5 m/s
(B) If the pelican was traveling at the same speed but was only 1.5 m above the water, how far would the fish travel horizontally before hitting the water below?
vertical height = 1.5 m
pelican's speed = 9.5 m/s
- lets also calculate the time it will take the fish to fall
s = ut + 
since u = 0
s = 
t =
where a = acceleration due to gravity and s = vertical height
t =
= 0.55 s
distance traveled by the fish = speed x time = 9.5 x 0.55 = 5.225 m
Answer:
A. Technician A only.B.
Explanation: The fuel system of a vehicle is made up of the fuel pump,the fuel filter,the injector or carburettor and the fuel tank. The main function of the fuel system is supply fuel to the engine of a vehicle. In order to check for leakage in the fuel system a small pressure smoke is usually installed in the fuel system.
Nitrogen at low pressure has also been used to check for leakage in the fuel system of a vehicle.
Density is mass divided by volume. rho=m/v. So, v=m/rho. In frank's case this is 80/8 = 10 cm^3.
To solve this problem we will apply the concepts related to the calculation of the surface, volume and error through the differentiation of the formulas given for the calculation of these values in a circle. Our values given at the beginning are


The radius then would be

And

PART A ) For the Surface Area we have that,

Deriving we have that the change in the Area is equivalent to the maximum error, therefore

Maximum error:


The relative error is that between the value of the Area and the maximum error, therefore:


PART B) For the volume we repeat the same process but now with the formula for the calculation of the volume in a sphere, so


Therefore the Maximum Error would be,



Replacing the value for the radius


And the relative Error


