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3 years ago

What can you tell from comparing these waves? Please help

Physics

2 answers:

umka21 [38]3 years ago

7 0

Answer:

Explanation:

Wave be is way less softer but wave a is softer you can see by the way it moves. You can also think about it as real waves from a beach, you can tell that wave a is softer.

elena-s [515]3 years ago

5 0

Answer:

Explanation:

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xander was traveling at a velocity of 4.5 m/s and 3.5 seconds. Finley was traveling at a velocity of 3.6 m/s for 4.2 seconds. Ma

iris [78.8K]

To compare and rank each one's acceleration, get the acceleration of each person by using the formula, Acceleration = Velocity/Time

Xander = 4.5mps / 3.5s = 1.29m/s^2
Finley = 3.6mps/4.2s = 0.86m/s^2
Max = 7.3mps/1.2s = 6.08m/s^2

Based on the answers above, the least acceleration was done by Finley, then Xander had higher acceleration than Finley, while most acceleration was done by Max.

3 0

3 years ago

While tuning a string to the note C at 523 Hz, a piano tuner hears 2.00 beats/s between a reference oscillator and the string.

lara31 [8.8K]

Answer:

a)the possible frequencies are 521hz ,522hz, 523, 524hz,525hz

b) 526hz

c)0.989 or a 1.14% decrease in tension

Explanation:

a) While tuning a string at 523 Hz,piano tuner hears 2.00 beats/s between a reference oscillator and the string.

The possible frequencies of the string can be calculated by

fl=f' - B

where

fl= lower limit of the possible frequency

f'= frequency of the string

B= beat heard by the tuner

fl= 523hz + Or - (2beats/secs * 1hz/1beat per sc)

fl= 521hz or 525hz

So the possible frequencies are 521hz ,522hz, 523, 524hz,525hz

b)fl=f' - B

523hz= f' - 3

f'= 523 + 3= 526hz

c) The tension is directly proportional to the square of the frequencies

T1/T2 =f1^2/f2^2

523^2 / 526^2 = 0.989 or a 1.14% decrease in tensio

6 0

3 years ago

______________ controls the flow of electric current.<br> Answer!!! <br> Please

stepladder [879]

Answer:

Explanation:

Its resistor

8 0

4 years ago

Two pistons of a hydraulic lift have radii of 2. 67 cm and 20. 0 cm, respectively. The downward force on the 2. 67-cm piston tha

Makovka662 [10]

The downward force on the 2. 67-cm piston that is required to lift a mass of 2000 kg supported by the 20-cm piston is 350 N.

<h3>What is pascal law?</h3>

Pressure applied to a closed system of fluid will be transfer at each point of the fluid and the boundaries of the system.

Let suppose at the two point of such system the input force apllied is F₁ and output force we get is F₂. The area of this points is A₁ and A₂ respectively. As the pressure at both point is same. Then by the pascal law,

$\dfrac{F_1}{A_1}=\dfrac{F_2}{A_2}\\$

In case of radius,

$\dfrac{F_1}{\pi r_1^2}=\dfrac{F_2}{\pi r_2^2}\\\\\dfrac{F_1}{r_1^2}=\dfrac{F_2}{ r_2^2}$

Two pistons of a hydraulic lift have radii of 2. 67 cm and 20. 0 cm, respectively. Thus,

$r_1=2.67\rm\; cm$

$r_2=20.0\rm\; cm$

The downward force on the 2. 67-cm piston that is required to lift a mass of 2000 kg supported by the 20-cm piston is The force applied on second piston is,

$F_2=mg\\F_2=2000\times9.81\\F_2=19620 \rm\; N$

Put the values in the above formula,

$\dfrac{F_1}{2.67^2}=\dfrac{19620}{20^2}\\F_1=\dfrac{19620\times2.67^2}{20^2}\\F_1\approx 350\rm\; N$

Thus, the downward force on the 2. 67-cm piston that is required to lift a mass of 2000 kg supported by the 20-cm piston is 350 N.

Learn more about the pascal law here;

brainly.com/question/4262025

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4 0

2 years ago

What region of the spectrum best corresponds to light with a wavelength equal to:_____ a. The diameter of a hydrogen atomb. The

zavuch27 [327]

We will make the comparison between each of the sizes against the known wavelengths.

In the case of the <em>hydrogen atom</em>, we know that this is equivalent to $10^{-10}$ m on average, which corresponds to the wavelength corresponding to X-rays.

In the case of the <em>Virus</em> we know that it is oscillating in a size of 30nm to 200 nm, so the size of the virus is equivalent to the range of the wavelength of an ultraviolet ray.

In the case of <em>height</em>, it fluctuates in a person around $10 ^ 0$ to $10 ^ 1$ m, which falls to the wavelength of a radio wave.

3 0

3 years ago