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3 years ago

What can you tell from comparing these waves? Please help

Physics

2 answers:

umka21 [38]3 years ago

7 0

Answer:

Explanation:

Wave be is way less softer but wave a is softer you can see by the way it moves. You can also think about it as real waves from a beach, you can tell that wave a is softer.

elena-s [515]3 years ago

5 0

Answer:

Explanation:

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The planet Jupiter has an acceleration due to gravity that is approximately 2.4 times as much as the earth (23.2 m s2 ). Which o

kumpel [21]

On Jupiter, C. your weight would increase by a factor of 2.4 . Weight is a product of mass and gravity. Mass does not change dependent upon location.

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4 years ago

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An astronaut whose mass is 80. kg and is initially at rest carries an empty oxygen tank with a mass of 10. kg. He throws the tan

sergeinik [125]

Answer:

0.25 m/s

Explanation:

From the law of conservation of momentum

Mu+ mu = Mv' + m v

M= mass of the astronaut = 80 kg

m= mass of the oxygen tank= 10 Kg

v= speedof the tank 2 m/s

u= initial velocity of the system= 0

If we substitute the values, we have

( 80× 0 )+(10×0)= [(80 x v )+ (10 x 2)]

0= 80v + 20

-20=80v

v= -0.25 m/s ( we have a negative value because the astronaut and the motion of the cylinder are in opposite direction)

Hence the velocity the astronaut start to move off into space is 0.25 m/s

6 0

3 years ago

Two capacitors, C1 = 25.0 μF and C2 = 31.0 μF, are connected in series, and a 6.0-V battery is connected across them.a. Find the

Brrunno [24]

Answer:

$13.83928\times 10^{-6}\ F$

$249.10704\times 10^{-6}\ J$

$137.89848\times 10^{-6}\ J$

$111.20842\times 10^{-6}\ J$

2.98273 V

Explanation:

$C_1=25\ mu F$

$C_2=31\ mu F$

V = Voltage = 6 V

Equivalent capacitance is given by

$\dfrac{1}{C}=\dfrac{1}{C_1}+\dfrac{1}{C_2}\\\Rightarrow C=\dfrac{C_1C_2}{C_1+C_2}\\\Rightarrow C=\dfrac{25\times 10^{-6}\times 31\times 10^{-6}}{(25+31)\times 10^{-6}}\\\Rightarrow C=13.83928\times 10^{-6}\ F$

Equivalent capacitance is $13.83928\times 10^{-6}\ F$

Energy stored is given by

$E=\dfrac{1}{2}CV^2\\\Rightarrow E=\dfrac{1}{2}\times 13.83928\times 10^{-6}\times 6^2\\\Rightarrow E=249.10704\times 10^{-6}\ J$

Total energy stored is $249.10704\times 10^{-6}\ J$

Charge is given by

$Q=CV\\\Rightarrow Q=13.83928\times 10^{-6}\times 6\\\Rightarrow Q=83.03568\times 10^{-6}\ C$

Voltage is given by

$V_1=\dfrac{Q}{C_1}\\\Rightarrow V_1=\dfrac{83.03568\times 10^{-6}}{25\times 10^{-6}}\\\Rightarrow V_1=3.3214272\ V$

$E_1=\dfrac{1}{2}C_1V_1^2\\\Rightarrow E_1=\dfrac{1}{2}\times 25\times 10^{-6}\times 3.3214272^2\\\Rightarrow E_1=137.89848\times 10^{-6}\ J$

Energy strored in C1 is $137.89848\times 10^{-6}\ J$

$V_2=\dfrac{Q}{C_2}\\\Rightarrow V_2=\dfrac{83.03568\times 10^{-6}}{31\times 10^{-6}}\\\Rightarrow V_2=2.67857\ V$

$E_2=\dfrac{1}{2}C_2V_2^2\\\Rightarrow E_2=\dfrac{1}{2}\times 31\times 10^{-6}\times2.67857^2\\\Rightarrow E_2=111.20842\times 10^{-6}\ J$

Energy stored in C2 is $111.20842\times 10^{-6}\ J$

$E=E_1+E_2\\\Rightarrow E=137.89848\times 10^{-6}+111.20842\times 10^{-6}\\\Rightarrow E=249.107\times 10^{-6}\ J$

So, the energy is equivalent

Equivalent capacitance

$C=C_1+C_2\\\Rightarrow C=25+31\\\Rightarrow C=56\times 10^{-6}\ F$

$E=\dfrac{1}{2}CV^2\\\Rightarrow V=\sqrt{\dfrac{2E}{C}}\\\Rightarrow V=\sqrt{\dfrac{2\times 249.107\times 10^{-6}}{56\times 10^{-6}}}\\\Rightarrow V=2.98273\ V$

The voltage would be 2.98273 V

8 0

4 years ago

Which of the following statements is true of space exploration?

elena-s [515]

You don't have a following space exploration

6 0

3 years ago

How much is the velocity of a body when it travels 600m in 5 minutes?

Gwar [14]

There are 60 minutes in an hour. Whatever distance a person crosses in 5 mins, he/she can cross 12 times that distance in 1 hour. So, in one hour the person could have crossed 12 X 600 = 7200 meters.

But, 1000 meters equal one kilometer. So, 7200m = 7.2 km. Thus, this person travels 7.2 km in one hour, and hence has a speed of 7.2 km/hr

7 0

3 years ago

Read 2 more answers