Explanation:
It is given that,
Mass of the brick, m = 1.15 kg
Radius of the circle, r = 1.44 m
The cable will break if the tension exceeds 43.0 N
Let v is the maximum sped can have at the bottom of the circle before the cable will break. At the bottom of the circle, the net force is equal to the centripetal force along with the weight of the brick. So,




v = 6.30 m/s
So, the maximum speed of the brick at the bottom of the circle before the cable will break is 6.3 m/s. Hence, this is the required solution.
"D. Both have electrons that orbit the atomic nucleus in a similar way ." is not shared by Bohr's model and the modern atomic model.
Hope this helps,
Davinia.
Answer:
-0.5 m/s^2
Explanation:
Acceleration = change in velocity / total time
7.5 / 15 = 0.5