Answer:
Kelly has read more of the book
Answer:
#carry on learning
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Find a point-slope form for the line that satisfies the stated conditions. Slope , passing through (-5,4)
I really need this question answered
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I don't see a value for the slope. We need that to set the equation, otherwise I can write an unlimited number of equations that pass through (-5,4).
I'll assume a slope so that you can see how the procedure would work. I like 6, so we'll assume a slope of 6.
The equation for a straight line has the form y = mx + b, where m is the slope and y is the y-intercept, the value of y when x = 0. We want a line that has slope 6, so:
y = 6x + b
We need to find b, so substitute the point (-5,4) that we know is on the line:
4 = 6*(-5) + b and solve for b
4 = -30 + b
b = 34
The line is y = 6x + 34
Answer:
The discriminant b2−4ac < 0, the equation has no real number solutions, it has complex solutions
Step-by-step explanation:
9x² - 4x + 1 = 0 ax² + bx + c = 0
The discriminant: b² - 4ac = (-4)² - 4*9*1 = 16 - 36 = -20
b2−4ac < 0, the equation has no real number solutions, it has complex solutions
160 minutes also known as 2 hours and 40 minutes
Answer:
hope it may help you
Step-by-step explanation:
n and n+14 are the numbers or you can use n and n-14; either way
n+n+14=58
2n+14=58
2n=58-14
2n=44
n=22 and n+14=22+14=36
22 and 36 are the numbers
or,...
58/2=29
29 and 29
28 and 30
27 and 31
26 and 32
25 and 33
24 and 34
23 and 35
22 and 36 answer
