Answer:
Carbons 1 and 3
Explanation:
We must remember that by definition <u>alpha carbon</u>s are the carbon (or carbons) next to the carbon that contains the main group. In this case, the main group is the carbonyl group (C = O) in the middle of the molecule. In the acetone molecule, we have three carbons, the carbons neighboring the carbon of the carbonyl group (carbon two) will be the <u>alpha carbons</u>. (Red and blue carbons or carbons one and three)
See figure 1 for further explanations.
I hope it helps!
Answer:
The wavelength, λ, of a photon that has an energy of E = 3.92×10⁻¹⁹ J is 5.054*10⁻⁷ m
Explanation:
The wavelength is defined for every periodic wave, that is, for the type of wave that repeats itself with exactly the same shape every given interval of time. It is the distance between two points from which the wave repeats.
Radiation is the emission, propagation and transfer of energy in any medium in the form of electromagnetic waves or particles.
The energy carried by electromagnetic radiation travels by waves. This energy is transmitted grouped in small "quanta" of energy called photons. The energy of a photon is measured in Joules (J) and is
Being:
- E=3.92×10⁻¹⁹ J
- h= 6.626×10⁻³⁴ J⋅s (Planck's constant)
- c = 2.99×10⁸ m/s (the speed of light)
- wavelength=?
and replacing:
you get:
wavelength= 5.054*10⁻⁷ m
<u><em>The wavelength, λ, of a photon that has an energy of E = 3.92×10⁻¹⁹ J is 5.054*10⁻⁷ m</em></u>
The missing question is:
<em>What is the percent efficiency of the laser in converting electrical power to light?</em>
The percent efficiency of the laser that consumes 130.0 Watt of electrical power and produces a stream of 2.67 × 10¹⁹ 1017 nm photons per second, is 1.34%.
A particular laser consumes 130.0 Watt (P) of electrical power. The energy input (Ei) in 1 second (t) is:
The laser produced photons with a wavelength (λ) of 1017 nm. We can calculate the energy (E) of each photon using the Planck-Einstein's relation.
where,
The energy of 1 photon is 6.52 × 10⁻²⁰ J. The energy of 2.67 × 10¹⁹ photons (Energy output = Eo) is:
The percent efficiency of the laser is the ratio of the energy output to the energy input, times 100.
The percent efficiency of the laser that consumes 130.0 Watt of electrical power and produces a stream of 2.67 × 10¹⁹ 1017 nm photons per second, is 1.34%.
You can learn more about lasers here: brainly.com/question/4869798
Atoum is the process of how large molecules are formed
Answer:
When electron jumps from high energy level to lower energy level.
Explanation:
The elctronic transition from one energy level to another energy level within the atom, always involve energy transitions.
The energy released or absorbed by electronic transition is always discrete and is called as " Photon". It means when electron jumps from when energy level to another energy level the energy released or absorbed is treated as photon emitted or absorbed.
When an electron jumps from higher energy level to a lower energy level, a photon of specific wavelength and specific energy is emitted in other words we can say that energy is released or emitted.
The energy of photon emitted or absorbed is easily calculated using Rydberg Formula which is simply the energy difference between the two energy levels and is given as under;
Ephoton = Eo ( 1 / n1^2 - 1 / n2 ^ 2)
In the above formula n1 is the initial energy level of electron and n2 is the final energy level of electron.
Eo = 13.6 eV ( Here "o" in Eo is in subscripts)
In n1 and n2 1 and 2 are in the subscripts.
^ represents that the disgits after them are exponents.
So by just putting the values of energy levels n1 and n2 we can easily calculate the value of energy of photon ( energy due to electronic transition) and compare the results that which transition will give high energy photon and which will give low energy photon.
