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belka [17]
3 years ago
8

How many grams of carbon are in 300 g of glucose

Chemistry
1 answer:
ankoles [38]3 years ago
5 0
There is 48 grams of carbon
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A galvanic cell is powered by the following redox reaction:2Fe+3(aq) + H2 (g) + 2OH−(aq) → 2Fe+2 (aq) + 2H2O (l)Answer the follo
ICE Princess25 [194]

Answer:

Anode: H₂(g) + 2 OH⁻(aq) → 2 H₂O(l) + 2 e⁻

Cathode: 2 Fe⁺³(aq) + 2 e⁻ → 2 Fe⁺²(aq)

E° = 1.60 V

Explanation:

Let's consider the reaction taking place in a galvanic cell.

2 Fe⁺³(aq) + H₂(g) + 2 OH⁻(aq) → 2 Fe⁺²(aq) + 2 H₂O(l)

The corresponding half-reactions are:

Anode (oxidation): H₂(g) + 2 OH⁻(aq) → 2 H₂O(l) + 2 e⁻   E°red = - 0.83 V

Cathode (reduction): 2 Fe⁺³(aq) + 2 e⁻ → 2 Fe⁺²(aq)        E°red = 0.77 V

The standard cell potential (E°) is the difference between the standard reduction potential of the cathode and the standard reduction potential of the anode.

E° = E°red, cat - E°red, an = 0.77 V - (-0.83 V) = 1.60 V

7 0
4 years ago
Earth orbits the____ in a imaginary plane called______
Montano1993 [528]
Earth orbits the sun in a imaginary plane called ecliptic 
8 0
3 years ago
Read 2 more answers
When swimmers get out of the pool and sit in the sun, their wet skin dries quickly. What happens to the water?
I am Lyosha [343]

Answer:

It evaporates and moves into the air.

Explanation:

When water is left out for a while, it evaporates into the air! :)

7 0
3 years ago
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How many formula units are in one mole of magnesium hydroxide?
svet-max [94.6K]

Answer:1 grams Magnesium Hydroxide is equal to 0.017146870490373 mole.

Explanation:The molecular formula for Magnesium Hydroxide is Mg(OH)2. The SI base unit for amount of substance is the mole.

7 0
4 years ago
Coal power plants burn large amounts of coal, c(s), in an o 2 ​ (g) atmosphere to generate electricity. the chemical reaction re
charle [14.2K]
Answer is: volume of carbon dioxide is 1,84·10⁸ l.
Chemical reaction: C + O₂ → CO₂.
m(C) = 100 t · 1000 kg/t = 100000 kg 
m(C) = 100000 kg · 1000 g/kg = 10⁸ g.
n(C) = m(C) ÷ M(C).
n(C) = 10⁸ g ÷ 12 g/mol.
n(C) = 8,33·10⁶ mol.
From chemical reaction: n(C) . n(CO₂) = 1 : 1.
n(CO₂) = 8,33·10⁶ mol.
m(CO₂) = 8,33·10⁶ mol · 44 g/mol.
m(CO₂)  = 3,66·10⁸ = 3,66·10⁵ kg.
V(CO₂) = 3,66·10⁵ kg ÷ 1,98 kg/m³ = 1,84·10⁵ m³.
V(CO₂) = 1,84·10⁵ m³ · 1000 l/m³ = 1,84·10⁸ l.

6 0
3 years ago
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