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sweet [91]
3 years ago
11

How much heat is added if 0.0318g of water is increased in temperature by 0.364 degrees C?

Chemistry
1 answer:
SSSSS [86.1K]3 years ago
8 0

Answer:

0.04838J

Explanation:

Heat is a form of energy that is transferred from one body to another as the result of a difference in temperature between the bodies , here heat is added to the water as a result of temperature change of 0.364 degreesC

Given:change in temperature=0.364

Mass of water=0.0318g

But we need specific heat capacity of water which is

4.2 J/g°C

Then we can calculate How much heat is added by using below formula

Energy = Mass * specific heat capacity *(change in temperature)

energy =0.0318g* 4.18g*0.364

=0.04838J

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Which element has a crystalline lattice through which electrons flow freely
xxTIMURxx [149]

Answer:

Copper

Explanation:

Metals are often arranged in crystalline lattices. The lattice consists of metal ions with an overlying sea of electrons. The conductivity of a metal depends on the nature of this crystal lattice. Naturally, some metals conduct electricity better than others. The unique properties of the crystal lattice of copper allow electrons to flow through it freely especially when it is drawn into a wire.

5 0
3 years ago
What is the equality in this reaction K+H2O-&gt;KHO+H2<br><br> Pls help me
Valentin [98]
KH2O? Maybe that will work?
6 0
3 years ago
Sodium hydroxide (a base) reacts with hydrochloric acid. After the reaction is complete, a pH indicator is added to the solution
fomenos

Answer:

hydrochloric acid

Explanation:

The hydrochloric acid in this reaction is the limiting reactant. A limiting reactant is the reactant that is used up in a chemical reaction. It determines the extent of the reaction.

Since the solution indicates a basic one after the end of the reaction, this suggests that more of the sodium hydroxide is still left unreacted with.

The reactant in excess supply here is the sodium hydroxide and the bulk of it is till left in solution.

7 0
3 years ago
ANSWER FAST!!
belka [17]

Answer: 800 mL of methyl alcohol should be added to 200 ml of water to make this solution.

Explanation:

Volume of the methyl alcohol = x

Volume of water = y = 200 mL

Volume of the solution ,V = x + y

Volume percentage of solution = 80%

x = 800 mL

800 mL of methyl alcohol should be added to 200 ml of water to make this solution.

4 0
2 years ago
A weak monoprotic acid is titrated with 0.100 MNaOH. It requires 50.0 mL of the NaOH solution to reach the equivalence point. Af
larisa86 [58]

Explanation:

The given reaction is as follows.

        HA(aq) + NaOH (aq) \rightleftharpoons NaA(aq) + H_{2}O(l)

Hence, number of moles of NaOH are as follows.

        n = 0.05 L \times 0.1 M

           = 0.005 mol

After the addition of 25 ml of base, the pH of a solution is 3.62. Hence, moles of NaOH is 25 ml base are as follows.

             n = 0.025 L \times 0.1 M

                = 0.0025 mol

According to ICE table,

         HA(aq) + NaOH (aq) \rightleftharpoons NaA(aq) + H_{2}O(l)

Initial:     0.005 mol   0.0025 mol              0                  0

Change: -0.0025 mol  -0.0025 mol        +0.0025 mol

Equibm:   0.0025 mol    0                         0.0025 mol

Hence, concentrations of HA and NaA are calculated as follows.

          [HA] = \frac{0.0025 mol}{V}

        [NaA] = \frac{0.0025 mol}{V}

       [A^{-}] = [NaA] = \frac{0.0025 mol}{V}

Now, we will calculate the pK_{a} value as follows.

          pH = pK_{a} + log \frac{A^{-}}{HA}

       pK_{a} = pH - log \frac{[A^{-}]}{[HA]}

                  = 3.42 - log \frac{\frac{0.0025 mol}{V}}{\frac{0.0025}{V}}

                  = 3.42

Thus, we can conclude that pK_{a} of the weak acid is 3.42.

           

8 0
3 years ago
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