Answer:
Copper
Explanation:
Metals are often arranged in crystalline lattices. The lattice consists of metal ions with an overlying sea of electrons. The conductivity of a metal depends on the nature of this crystal lattice. Naturally, some metals conduct electricity better than others. The unique properties of the crystal lattice of copper allow electrons to flow through it freely especially when it is drawn into a wire.
KH2O? Maybe that will work?
Answer:
hydrochloric acid
Explanation:
The hydrochloric acid in this reaction is the limiting reactant. A limiting reactant is the reactant that is used up in a chemical reaction. It determines the extent of the reaction.
Since the solution indicates a basic one after the end of the reaction, this suggests that more of the sodium hydroxide is still left unreacted with.
The reactant in excess supply here is the sodium hydroxide and the bulk of it is till left in solution.
Answer: 800 mL of methyl alcohol should be added to 200 ml of water to make this solution.
Explanation:
Volume of the methyl alcohol = x
Volume of water = y = 200 mL
Volume of the solution ,V = x + y
Volume percentage of solution = 80%
x = 800 mL
800 mL of methyl alcohol should be added to 200 ml of water to make this solution.
Explanation:
The given reaction is as follows.

Hence, number of moles of NaOH are as follows.
n = 
= 0.005 mol
After the addition of 25 ml of base, the pH of a solution is 3.62. Hence, moles of NaOH is 25 ml base are as follows.
n = 
= 0.0025 mol
According to ICE table,

Initial: 0.005 mol 0.0025 mol 0 0
Change: -0.0025 mol -0.0025 mol +0.0025 mol
Equibm: 0.0025 mol 0 0.0025 mol
Hence, concentrations of HA and NaA are calculated as follows.
[HA] = 
[NaA] = 
![[A^{-}] = [NaA] = \frac{0.0025 mol}{V}](https://tex.z-dn.net/?f=%5BA%5E%7B-%7D%5D%20%3D%20%5BNaA%5D%20%3D%20%5Cfrac%7B0.0025%20mol%7D%7BV%7D)
Now, we will calculate the
value as follows.
pH = 
![pK_{a} = pH - log \frac{[A^{-}]}{[HA]}](https://tex.z-dn.net/?f=pK_%7Ba%7D%20%3D%20pH%20-%20log%20%5Cfrac%7B%5BA%5E%7B-%7D%5D%7D%7B%5BHA%5D%7D)
= 
= 3.42
Thus, we can conclude that
of the weak acid is 3.42.