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3 years ago

compound 1 contains 15.0g of hydrogen and 120.0g oxygen. What is the percent compound of each element?

Chemistry

1 answer:

allsm [11]3 years ago

8 0

Note down the formula below

$\boxed{\sf Mass\%\;of\; element=\dfrac{Mass\:of\:the\: element}{Mass\;of\:the\: compound}\times 100}$

Mass of the compound

$\\ \sf\longmapsto 15+120=135g$

Mass % of Hydrogen:-

$\\ \sf\longmapsto \dfrac{15}{135}\times 100$

$\\ \sf\longmapsto \dfrac{1}{9}\times 100$

$\\ \sf\longmapsto 11.1\%$

Mass % of Oxygen:-

$\\ \sf\longmapsto \dfrac{120}{135}\times 100$

$\\ \sf\longmapsto \dfrac{8}{9}\times 100$

$\\ \sf\longmapsto 88.9\%$

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Answer:

the equilibrium concentration of [PCl₅] is 3.64*10⁻³ M

Explanation:

for the reaction

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where

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and [A] denote concentrations of A

if initially the mixture is pure PCl₅ , then it will dissociate according to the reaction and since always one mole of PCl₃(g) is generated with one mole of Cl₂(g) , the total number of moles of both at the end is the same → they have the same concentration → [PCl₃(g)] = [Cl₂]=0.27 M

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[PCl₅] = 3.64*10⁻³ M

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<u />

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