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Sergio039 [100]
3 years ago
7

Using Hooke's law, F s p r i n g = k Δ x , find the distance a spring with an elastic constant of 4 N/cm will stretch if a 2 new

ton force is applied to it.
1/2cm


2 cm


4 cm


8 cm
Chemistry
2 answers:
irakobra [83]3 years ago
6 0

1/2cm

just took the test and this is the right answer

ki77a [65]3 years ago
3 0
I think it is the first option 1/2 cm.
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The characteristic odor of pineapple is due to ethyl butyrate, a compound containing carbon, hydrogen, and oxygen. Combustion of
gavmur [86]

<u>Answer:</u> The empirical formula for the given compound is C_3H_6O

<u>Explanation:</u>

The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:

C_xH_yO_z+O_2\rightarrow CO_2+H_2O

where, 'x', 'y' and 'z' are the subscripts of Carbon, hydrogen and oxygen respectively.

We are given:

Conversion factor:  1 g = 1000 mg

Mass of CO_2=6.32mg=0.00632g

Mass of H_2O=2.58g=0.00258g

Mass of compound = 2.78 mg = 0.00278 g

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

  • <u>For calculating the mass of carbon:</u>

In 44g of carbon dioxide, 12 g of carbon is contained.

So, in 0.00632 g of carbon dioxide, \frac{12}{44}\times 0.00632=0.00172g of carbon will be contained.

  • <u>For calculating the mass of hydrogen:</u>

In 18g of water, 2 g of hydrogen is contained.

So, in 0.00258 g of water, \frac{2}{18}\times 0.00258=0.000286g of hydrogen will be contained.

  • Mass of oxygen in the compound = (0.00278) - (0.00172 + 0.000286) = 0.000774 g

To formulate the empirical formula, we need to follow some steps:

  • <u>Step 1:</u> Converting the given masses into moles.

Moles of Carbon =\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{0.00172g}{12g/mole}=1.43\times 10^{-4}moles

Moles of Hydrogen = \frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.000286g}{1g/mole}=2.86\times 10^{-4}moles

Moles of Oxygen = \frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{0.000774g}{16g/mole}=4.83\times 10^{-5}moles

  • <u>Step 2:</u> Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 4.83\times 10^{-5}mol

For Carbon = \frac{1.43\times 10^{-4}}{4.83\times 10^{-5}}=2.96\approx 3

For Hydrogen  = \frac{2.86\times 10^{-4}}{4.83\times 10^{-5}}=5.92\approx 6

For Oxygen  = \frac{4.83\times 10^{-5}}{4.83\times 10^{-5}}=1

  • <u>Step 3:</u> Taking the mole ratio as their subscripts.

The ratio of C : H : O = 3 : 6 : 1

Hence, the empirical formula for the given compound is C_3H_{6}O_1=C_3H_6O

3 0
3 years ago
A lamp releases only light and thermal energy. The energy input of the lamp is 120 watts. Of that input, 80 watts is converted t
fomenos
40 watts because 120-80 is forty or 80 + 40 - 120
6 0
3 years ago
2. When vinegar is added to eggshells, carbon dioxide gas is produced.​Why?
skad [1K]

Answer:

same as his

Explanation:

4 0
3 years ago
A piece of wood near a fire is at 23°c. it gains 1,160 joules of heat from the fire and reaches a temperature of 42°c. the speci
Alex73 [517]

The mass of the piece of wood is 35.58 g.

Joule = M × T × C

Where, M = mass

T = change in temperature(42C-23C=19 C)

C = specific heat capacity = 1.716 joules/gram

Substituting the values in the equation,

1160 = M × 19 × 1.716

M = 1160/32.604 = 35.58 g

Therefore, the mass of the piece of wood = 35.58 g

<h3>What is meant by specific heat capacity?</h3>

A material's specific heat capacity, which is defined as its heat capacity divided by its mass, determines how much energy is required to increase a gram's temperature by one degree Celsius (or one Kelvin)

<h3>What is mass?</h3>

Mass is the quantity of matter in a physical body.

To learn more about specific heat capacity visit:

brainly.com/question/1747943

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7 0
1 year ago
Consider only the experiment you conducted with 0.5 g. of lactose.
rjkz [21]
Answer is: <span>the pH value(level) is the independent variable.</span><span>
</span>
Missing question: <span>We conducted an experiment where we added 0.5 g of lactose to 5 different test tubes all containing 5 different pH levels. What is the independent variable?
In this experiment pH level changes, so results depend on different pH values.
Mass of lactose is same during experiment,so t</span>he number of molecules of product formed per minute is the <span>dependent variable.</span>
8 0
3 years ago
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