Answer: 94.13 L
Explanation: In STP in an ideal gas there is a standard value for both temperature and pressure. At STP,pressure is equal to 1atm and the temperature at 0°C is equal to 273.15K. This problem is an ideal gas so we use PV=nRT where R is a constant R= 0.08205 L.atm/mol.K.
To find volume, derive the equation, it becomes V=nRT/P. Substitute the values. V= 4.20 mol( 0.08205L.atm/mol.K)(273.15K) / 1 atm = 94.13 L. The mole units, atm and K will be cancelled out and L will be the remaining unit which is for volume.
Answer: 7.07 grams
Explanation:
To calculate the moles :


According to stoichiometry :
1 mole of
require 1 mole of 
Thus 0.052 moles of
will require=
of 
Thus
is the limiting reagent as it limits the formation of product and
is the excess reagent.
As 1 mole of
give = 1 mole of 
Thus 0.052 moles of
give =
of 
Mass of 
Thus 7.07 g of
will be produced from the given masses of both reactants.
It can hold 4 minutes more electrons.
5600 why because you take away and then you add then yeah