A jumbo jet start from rest an acceleration of 3m/s and makes a run for 35s before taking off,what is the minimum length of the
runway?what is it velocity at take off?
1 answer:
Answer:
Explanation:
Assuming you mean acceleration is 3 m/s²
s = s₀ + ut + ½at²
d = 0 + 0(35) + ½(3)35² = 1,837.5 m
v = u + at
v = 0 + 3(35) = 105 m/s
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