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Natali [406]
3 years ago
15

what is the kinetic energy of an object that as a mass of 12 kilograms and moves with the velocity of 10 m/s

Physics
1 answer:
Galina-37 [17]3 years ago
7 0

Answer:

120 m/s

Explanation: QUIZLET

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What happens when the voltage increases and the resistance stays the same in a electrical circuit?
Orlov [11]

Answer:

The current in the circuit increases

Explanation:

The ohm's law states that the potential across a circuit is proportional to the current in the circuit.

                                             V ∝ I

Where 'V' is the potential difference across the circuit and 'I' is the current in the circuit.

The proportionality constant present in the equation is the resistance of the circuit. Hence, the equation becomes

                                             V = IR

According to the equation, when V is directly proportional to 'I' where 'R' remains as constant, then the change in 'V is brings change in 'I' to make the equation valid.

So, when there is an increase in the voltage, the current on the circuit increases.

4 0
3 years ago
A 0.49-kg cord is stretched between two supports, 7.8m apart. When one support is struck by a hammer, a transverse wave travels
katovenus [111]

To solve this problem we will apply the laws of Mersenne. Mersenne's laws are laws describing the frequency of oscillation of a stretched string or monochord, useful in musical tuning and musical instrument construction. This law tells us that the velocity in a string is directly proportional to the root of the applied tension, and inversely proportional to the root of the linear density, that is,

v = \sqrt{\frac{T}{\mu}}

Here,

v = Velocity

\mu= Linear density (Mass per  unit length)

T = Tension

Rearranging to find the Period we have that

T = v^2 \mu

T = v^2 (\frac{m}{L})

As we know that speed is equivalent to displacement in a unit of time, we will have to

T = (\frac{L}{t}) ^2(\frac{m}{L})

T = (\frac{7.8}{0.83})^2 (\frac{0.49}{7.8})

T = 5.54N

Therefore the tension is 5.54N

8 0
3 years ago
A person is going to take a trip from town eight to town D to do this they travel 60 KM in .45 hour And then stop in town before
ANEK [815]

Answer:

   v = 72 km / h

Explanation:

The definition of average speed is the distance traveled between the time interval

          v = Δx / Δt

let's find the distance traveled

       x = 60 + 30

       x = 90 km

time spent, all time must be included, travel time and when stopped

       t = 0.45 + 0.15 + 0.5+ 0.15

       t = 1.25 h

we substitute in the initial equation

      v = 90 / 1.25

       v = 72 km / h

in going from one city to the other

4 0
3 years ago
A joule equals the amount of work done on an object when a force _______ displaces that object ______.
Anastaziya [24]

Answer:

A joule equals the amount of work done on an object when a force <u>of</u><u> </u><u>1</u><u> </u><u>Newton</u><u> </u> displaces that object <u>1</u><u> </u><u>metre</u>

3 0
3 years ago
Molybdenum has the BCC crystal structure, has a density of 10.22 g cm-3 and an atomic mass of 95.94 g mol-1. What is the atomic
puteri [66]

Answer:

atomic concentration = 2 atoms/unit cell

lattice parameter: a= 3.22 x 10⁻¹⁰ m

atomic radius: r= 1.39 x 10⁻¹⁰m

Explanation:

The atomic concentration is the number of atoms that can fit into a unit cell. It is a known number for each unit cell crystal structure. For a BCC (body-centered cube) crystal structure, atomic concentration is 2 atoms/unit cell because there are a 1/8 part of an atom in each corner of the cube (1/8 x 8= 1 atom) and 1 central atom in the central position of the cube ⇒ n= 1 atom + 1 atom= 2 atoms/unit cell

In order to calculate the lattice parameter a, we introduce the atomic mass 95.94 g/mol and the density 10.22 g/cm³ in the expression for the volume of the cube:

Vc= a³= \frac{(95.94 g/mol) x (2 atoms/unit cell)}{(10.2 g/cm^{3}) x (6.023 x 10^{23} atoms/mol)  }

a³= 3.12 x 10⁻²³ m³

⇒ a = ∛(3.12 x 10⁻²³ m³) = 3.22 x 10⁻¹⁰m

Once we know the lattice parameter a, we can calculate the atomic radius r by using the expression of a for a BCC structure:

a= \frac{4r}{\sqrt{3}}

⇒ r= a x √3/4= (3.22 x 10⁻¹⁰ m) x √3/4 = 1.39 x 10⁻¹⁰ m

5 0
3 years ago
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