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Olin [163]
3 years ago
12

Find the middle term of the expansion of

Mathematics
1 answer:
Sladkaya [172]3 years ago
6 0

Answer:

i think it is C

Step-by-ste explanation:

You might be interested in
Calculate the speed of a car that went a distance of 125 miles in 2 hours<br> time.
DerKrebs [107]

Answer:

62.5

Step-by-step explanation:

speed = distance / time taken

= 125/2

=62.5miles per hour

5 0
3 years ago
What is the quotient?
yuradex [85]

Answer:

-1.58208955224

Step-by-step explanation:

DO THE MATH

5 0
2 years ago
You want to calculate the displacement of an object thrown over a bridge. Using -10 m/s^2 for acceleration due to gravity, what
MrRissso [65]

<u>Answer</u>

<em>The total displacement of the object is 320 m</em>

<u>Solution-</u>

From the formulas of mechanics,

s=ut+\frac{1}{2}at^{2}

Where,

s = displacement

u = initial velocity = 0               ( ∵ As the body was in rest in the beginning )

t = time taken = 8 s

a = acceleration = -10 m/s²      ( ∵ -ve is because of the downward motion)

Putting all the values,

s= 0 \times 8 + \frac{1}{2}(-10)8^{2} = -320 \ m ( ∵ -ve displacement means it is in downwards)

5 0
3 years ago
Determine whether the set of vectors is a basis for ℛ3. Given the set of vectors , decide which of the following statements is t
schepotkina [342]

Answer:

(A) Set A is linearly independent and spans R^3. Set is a basis for R^3.

Step-by-Step Explanation

<u>Definition (Linear Independence)</u>

A set of vectors is said to be linearly independent if at least one of the vectors can be written as a linear combination of the others. The identity matrix is linearly independent.

<u>Definition (Span of a Set of Vectors)</u>

The Span of a set of vectors is the set of all linear combinations of the vectors.

<u>Definition (A Basis of a Subspace).</u>

A subset B of a vector space V is called a basis if: (1)B is linearly independent, and; (2) B is a spanning set of V.

Given the set of vectors  A= \left(\begin{array}{[c][c][c][c]}1 & 0 & 0 & 0\\ 0 & 1 & 0 & 1\\ 0 & 0 & 1 & 1\end{array} \right) , we are to decide which of the given statements is true:

In Matrix A= \left(\begin{array}{[c][c][c][c]}(1) & 0 & 0 & 0\\ 0 & (1) & 0 & 1\\ 0 & 0 & (1) & 1\end{array} \right) , the circled numbers are the pivots. There are 3 pivots in this case. By the theorem that The Row Rank=Column Rank of a Matrix, the column rank of A is 3. Thus there are 3 linearly independent columns of A and one linearly dependent column. R^3 has a dimension of 3, thus any 3 linearly independent vectors will span it. We conclude thus that the columns of A spans R^3.

Therefore Set A is linearly independent and spans R^3. Thus it is basis for R^3.

8 0
3 years ago
(x-y) (x-1,y+3) (I need the answer pls)
SVEN [57.7K]

Answer:

x² - 2xy + 3x + y² - 3y

Step-by-step explanation:

1: Multiply the second parentheses by each term from the first parentheses

X x(x - 1 y + 3) - y x (x - 1y + 3)

2: Distribute x through parentheses

4 0
3 years ago
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